This problem is about conversion and dimensional analysis. Important information to know:
1 atm = 760 torr = 101.325 kPa
For atm to torr conversion:
0.875 atm * (760 torr / 1 atm) = 665 torr
For atm to kPa conversion:
0.875 atm * (101.325 kPa / atm) = 88.7 kPa
Thus the answer is b) 665 torr and 88.7 kPa
0.3147 concentration (in moles/l) of a saline (NaCl) solution will provide an isotonic eyedrop solution.
Isotonic eye drops
Because it might result in eye discomfort or tissue damage if it is not maintained, isotonicity is regarded as a crucial component of ophthalmic medicines. A few drops of blood are mixed with the test preparation before being examined and judged under a microscope at a magnification of 40. Isotonic solutions are those that have the same amount of water and other solutes in them as the cytoplasm of a cell. Since there is no net gain or loss of water, placing cells in an isotonic solution will not cause them to either shrink or swell.
We can calculate the osmotic pressure exerted by a solution using the following expression.
π = M . R . T
where,
π is the osmotic pressure
M is the molar concentration of the solution
R is the ideal gas constant
T is the absolute temperature
The absolute temperature is 37 + 273 = 310 K
π = M . R . T
8 = (X mol/L) . (0.082atm.L/mol.K) . 310 K = 0.3147 mol/L
To learn more about osmotic pressure refer:
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Answer: 
Explanation:Bond energy of H-H is 436.4 kJ/mole
Bond energy of C-H is 414 kJ/mol
Bond energy of C=C is 620 kJ/mol
Bond energy of C≡C is 835 kJ/mol
= {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}
<span>Van der waal or ideal eqn is given by PV = NRT; P = NRT/ V.
Where N = 1.335 is the number of moles. T = 272K is temperature. V = 4.920L is the volume. And R = 0.08205L. Substiting the values into the eqn; we have,
P = (1.331* 0.08205 * 272)/ 4.920 = 29.7047/ 4.920 = 6.03atm.</span>
Answer:
Different materials have different densities. So it is False
