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White raven [17]
3 years ago
10

Show two data points from your simulation that demonstrate this behavior.

Physics
1 answer:
Anestetic [448]3 years ago
3 0

Answer:

hello your question is incomplete attached below is the complete and the required circuit diagrams

answer :

Ai) <em>This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well</em>

B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature

hence At 0 mA current, there won't be any noticeable change

Explanation:

Ai) The voltage across the resistor will double when you double the current through the resistor

Given that : V = I*R.  

lets assume : I = 2 amperes , R = 3 ohms

V = 2*3 = 6 v

secondly lets assume double the value of  (I)   i.e. I = 4 amperes

hence : V = 4*3 = 12 volts

<em>This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well</em>

Aii) Showing the two data points from simulation

I1                    V1            I2= 2I1         V2=2V1       V1/ I1 =V2/I2

0.9*10^3     9 * 10^3     1.8*10^3       18*10^3          10 ohms

1.6 * 10^3    16 * 10^3    3.2*10^3     32*10^3         10 ohms

B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature

hence At 0 mA current, there won't be any noticeable change

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Explanation:

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Number of moles mono atomic gas A ,   n 1  =  4 .2 mol

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Initial energy of gas A ,   K A  =  9500  J

Thermal energy given by gas A to gas B ,   Δ K  =  600 J

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Let  K B  be the initial energy of gas B.

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Energy of the gas B after mixing can be written as

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⟹ KB = [(3/2) x 3.2 x 8.314 x 382.32] - 600

⟹ KB = 14657.32 J

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