Question

Click Stop Using the slider set the following: coeff of restitution to 1.00 A velocity (m/s) to 6.0 A mass (kg) to 6.0 B velocity (m/s) to 0.0 Calculate what range can the mass of B be to cause mass A to bounce off after the collision. Calculate what range can the mass of B be to cause mass A to continue forward after the collision. Check your calculations with the simulation. What are the ranges of B mass (kg)

Answer 1

Answer:

$M_b=6kg$

Explanation:

From the question we are told that:

Coefficient of restitution $\mu=1.00$

Mass A $M_a=6kg$

Initial Velocity of A $U_a=6m/s$

Initial Velocity of B $U_b=0m/s$

Generally the equation for Coefficient of restitution is mathematically given by

 $\mu=\frac{V_b-V_a}{U_a-U_b}$

 $1=\frac{v_B}{6}$

 $V_b=6*1$

 $V_b=6m/s$

Generally the equation for conservation of linear momentum  is mathematically given by

 $M_aU_a+M_bU_b=M_aV_a+M_bV_b$

 $6*6+=M_b*6$

 $M_b=6kg$