A) 1s on H and 3p on Cl
In HCl, the H atom has only one valance electron. Each share an electron an therefore a single covalent bond is formed between the two. The bond in HCl is therefore a result of an overlap between 1s orbital and ONLY ONE of the lobes of the 3p orbital of Chlorine.
Answer: Mass of
required to form 930 kg of iron is 1328 kg
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
For iron:
Given mass of iron = 930 kg = 930000 g (1kg=1000g)
Molar mass of iron = 56 g/mol
Putting values in equation 1, we get:

The chemical equation for the production of iron follows:

By Stoichiometry of the reaction:
2 moles of iron are produced by = 1 mole of 
So, 16607 moles of iron will be produced by =
of 
Now, calculating the mass of
from equation 1, we get:
Mass of
= 
Thus mass of
required to form 930 kg of iron is 1328 kg
Answer:
option C = 9.0 x 10²³ atoms
Explanation:
Data Given:
no. of moles of tin (Sn) atoms = 1.5 moles
no. of tin (Sn) atoms = ?
Solution:
Formula used to find number of atoms
no. of moles = no. of atoms / Avogadro's number
Rearrange the above equation:
no. of atoms = no. of moles x Avogadro's number . . . . . . (1)
Where
Avogadro's number = 6.022 x 10²³
Put values in equation 1
no. of atoms = 1.5 x 6.022 x 10²³
no. of atoms = 9.033 x 10²³
Round the figure = 9.0 x 10²³ atoms
So option C is correct
Answer:
That something has changed chemically
Explanation:
Uh...Google it
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