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Serga [27]
3 years ago
13

A ball is thrown vertically upward with an initial velocity of 23 m/s. What are its position and velocity after 2 s?

Physics
1 answer:
Anastasy [175]3 years ago
7 0

Answer:

  • The position of the ball after 2 s is 26.4 m
  • The velocity of the ball after 2 s is 3.4 m/s

Explanation:

Given;

initial velocity of the ball, u = 23 m/s

time of motion, t = 2 s

The position of the ball after 2 s is given by;

h = ut - ¹/₂gt²

h = (23 x 2) - ¹/₂ x 9.8 x 2²

h = 46 - 19.6

h = 26.4 m

The velocity of the ball after 2 s is given by;

v² = u² + 2(-g)h

v² = u² - 2gh

v² = 23² - (2 x 9.8 x 26.4)

v² = 529 - 517.44

v² = 11.56

v = √11.56

v = 3.4 m/s

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