Question

Some gas was collected when the pressure was 760mmHg. It occupied 500mL when the pressure was increased to 800mmHg. What was the original volume of the gas?

Answer 1

Answer:

The answer is 526.32 mL

Explanation:

To find the original volume we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the original volume

$V_1 = \frac{P_2V_2}{P_1}$

From the question we have

$V_1 = \frac{500 \times 800}{760} = \frac{400000}{760} = \frac{40000}{76} \\ = 526.315789...$

We have the final answer as

526.32 mL

Hope this helps you