The formula we're gonna use for this problem is written below:
ΔG°= nFE°
where
n is number of mol electrons displaced in the reaction
F is Faraday's constant = 96,500 C/mol e
E° is the standard emf
ΔG° = (2)(96,500)(1.46) = <em>281,780 Joules</em>
The HNO3 is considered to be a Bronsted - Lowry acid, when this substance 'HNO3', will donate a proton, then it will form another substance. It will form two substances when the proton is donated in the water molecule. The two substances that will be formed is a nitrate iron and a hydronium ion.
Answer:
The correct answer is 0.206 moles
Explanation:
According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:
Given that
Amount of 
is 11.0 grams
And, the volume is 235 mL
Now the molar mass of is 53.49g/mol
So, the number of moles presented is
= 11.0 ÷ 53.49
= 0.206 moles
hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles
To solve for the number of moles, we simply have to use the Avogadros number which states that there are 6.022 x 10^23 molecules per mole. Therefore:
number of moles = 6.67 X 10^40 chlorine molecules / (6.022 x 10^23 molecules / mole)
number of moles = 1.108 x 10^17 moles
