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3 years ago

A car goes 20 mph to 10 mph in five seconds find its acceleration

1 answer:

3 0

C.-2 miles per hour per second
Explanation;
Acceleration = change in velocity / time
Acceleration = (final velocity - initial velocity )/time
Acceleration = (v - u)/t
Given: u = 20 miles per hour, v = 10 miles per hour
t = 5 seconds
Acceleration = (10 - 20)/5
Acceleration = -10/5
Acceleration = -2 miles per hour per second

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Soap bubble interference Light of 690-nm wavelength interferes constructively when reflected from a soap bubble having refractiv

Nikitich [7]

Answer:

The two possible thicknesses of the soap bubble is 129 nm and 389 nm.

Explanation:

Given that,

Wavelength = 690 nm

Refractive index = 1.33

We need to calculate the two possible thicknesses of the soap bubble

Using formula of thickness

$t=\dfrac{(m+\dfrac{1}{2})\lambda}{2n}$

For m = 0,

Put the value into the formula

$t=\dfrac{\dfrac{690\times10^{-9}}{2}}{2\times1.33}$

$t=129\times10^{-9}\ m$

$t=129\ nm$

For m=1,

Put the value into the formula

$t=\dfrac{\dfrac{3\times690\times10^{-9}}{2}}{2\times1.33}$

$t=389\times10^{-9}\ m$

$t=389\ nm$

Hence, The two possible thicknesses of the soap bubble is 129 nm and 389 nm.

5 0

3 years ago

D. 'g' vanishes at centre of

guapka [62]

Answer:

a. 0.8 cm

Explanation:

The distance of the object from the lens, u = 1 cm

The magnification of the lens, m = 5

The focus of a lens formula is given as follows;

$f = \dfrac{1}{\dfrac{1}{v} + \dfrac{1}{v} }$

The magnification of the lens, m = -v/u

Where;

v = The distance of the image from the lens

Therefore, we have;

v = m × u

∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)

From which we get;

$f = \dfrac{1}{\dfrac{1}{1} + \dfrac{1}{5} } = \dfrac{5}{6} \approx 0.8$

The focal length ≈ 0.8 cm

6 0

3 years ago

Four students are carrying out different laboratory procedures.

leva [86]

B. Jason's experiment

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4 years ago

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Ivanshal [37]

I think it’s 10 kg since 20/2=10

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3 years ago

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Inappeopiate pratices: what it means? Why it not good idea to use these?

Rina8888 [55]

Answer:

Inappropriate practice is conduct by a practitioner in connection with rendering or initiating services that a practitioner's peers could reasonably conclude was unacceptable to the general body of their profession.

Explanation:

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4 years ago