Question

Hydrogen reacts with nitrogen monoxide to form dinitrogen monoxide (aughing gas) according to the equation: H2 (9) + 2 NOg) N20() + H20G) Based on the following data: H2 (M) NO (M) Rate (M*s) Trial 1 0.30 0.35 2.835 x 10-3 Trial 2 0.60 0.35 1.134 x 10-2 Trial 3 0.60 0.70 2.268 x 10-2 a. What is the order with respect to H2? b. What is the order with respect to NO? c. What is the rate equation for this reaction? d. Calculate the rate constant for the reaction.

Answer 1

Explanation:

H2 (9) + 2 NOg) N20() + H20G)

H2 (M) NO (M) Rate (M*s)

Trial 1 0.30 0.35 2.835 x 10-3

Trial 2 0.60 0.35 1.134 x 10-2

Trial 3 0.60 0.70 2.268 x 10-2

a. What is the order with respect to H2?

Comparing trials 1 and 2,the concentration of H is doubled and that leads to an increase in the rate of the reaction by a factor of 4. This means the order with respect to H is 2.

b. What is the order with respect to NO?

Comparing trials 2 and 3, the concentration of NO is doubled and that leads to an increase in the rate of the reaction by a factor of 2. This means the order with respect to NO is 1.

c. What is the rate equation for this reaction?

rate = k [H]²[NO]

d. Calculate the rate constant for the reaction.

Taking trial 1;

rate = k [H]²[NO]

2.835 x 10-3  = k (0.30)² (0.35)

k = 90 x 10-3 = 0.09  L2 mol-2 s-1