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3 years ago

6

A current-carrying wire 0.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10.0 A and there

is a resultant force of 3.0 N on the wire due to the interaction of the current and field, what is the magnetic field strength?

1 answer:

____ [38]3 years ago

7 0

<em>Answer</em>

0.6 teslas

<em>Explanation</em>

When a conductor is inside a magnetic field it experiences a force given by;

Force = ILBsinθ

Where I⇒ current

L ⇒length of the conductor

B ⇒ magnetic field strength

θ ⇒ Angle between the conductor and magnetic field.

F = ILBsinθ

When θ = 90°, Then sin 90 =1 and the formula becomes;

F =ILB

3 = 10 × 0.5 × B

3 = 5B

B = 3/5

= 0.6

magnetic field strength = 0.6 teslas

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