A hydraulic lift raises a 2 000-kg automobile when a 500-N force is applied to the smaller piston. If the smaller piston has an
1 answer:
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Answer:
Magnetic dipole moment is 0.0683 J/T.
Explanation:
It is given that,
Length of the rod, l = 7.3 cm = 0.073 m
Diameter of the cylinder, d = 1.5 cm = 0.015 m
Magnetization,
The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :
Where
r is the radius of rod, r = 0.0075 m
So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.