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Ivahew [28]
3 years ago
3

.) Identify the following quantities as scalar or vector: the mass of an object, the number of leaves on a tree, wind velocity.

Physics
2 answers:
Vladimir79 [104]3 years ago
5 0

Answer:

C

Explanation:

mass is a scalar quantity, number of anything is also a scalar quantity, since it lacks direction, and wind velocity is a vector quantity

VikaD [51]3 years ago
5 0
C is the answer hops this helps ;)
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The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-1
telo118 [61]
<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>

Explanation:

The half-life h of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this case, we are given the half life of two elements:

beryllium-13: h_{B-13}=5(10)^{-10}s=0.0000000005s

beryllium-15: h_{B-15}=2(10)^{-7}s=0.0000002s

As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?

We can find it out by the following expression:

h_{B-15}=X.h_{B-13}

Where X is the amount we want to find:

X=\frac{h_{B-15}}{h_{B-13}}

X=\frac{2(10)^{-7}s}{5(10)^{-10}s}

Finally:

X=400

Therefore:

The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.

8 0
3 years ago
A sound wave, with speed of 340 m/s has a frequency of 17,000 Hz. What
Fiesta28 [93]
Wavelength = speed / frequency = 340 / 17000 = 0.02 m
6 0
3 years ago
An elements atomic number is 85 how many protons would an atom of this element have?
garik1379 [7]

85 protons are in astatine have.

5 0
3 years ago
Read 2 more answers
An aircraft has a mass of 3.30 x 105 kg. At a certain instant during its landing, its speed is 45.2 m/s. If the braking force is
melamori03 [73]
Ultraconservative the future and I have been working with the following questions.
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4 years ago
The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
const2013 [10]

Answer:

fr = ½ m v₀²/x

Explanation:

This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.

The best way to solve this exercise is to use the energy work theorem

            W = ΔK

Where work is defined as the product of force by distance

           W = fr x cos 180

The angle is because the friction force opposes the movement

          Δk =K_{f} –K₀

          ΔK = 0 - ½ m v₀²

We substitute

         - fr x = - ½ m v₀²      

           fr = ½ m v₀²/x

8 0
4 years ago
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