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vekshin1
2 years ago
15

What is the difference in PE

Physics
1 answer:
Blababa [14]2 years ago
3 0

Answer:

831.4 J

Explanation:

Info given:

mass adult: 82.5kg

mass child: 14.7kg

height of wall: 1.25m

g = 9.81m/s^2

PE = mgh

For adult:

mgh = (82.5kg)(9.81m/s^2)(1.25m) = 1011.65 J

For child:

mgh = (14.7kg)(9.81m/s^2)(1.25m) = 180.25 J

Difference in PE: 1011.65 J - 180.25 J = 831.4 J

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A) current 

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2 years ago
Un Esquiador Inicia un Salto Horizontal con una velocidad Inicial de 25 m/s. La Altura al Final de la Rampa es de 80 m del punto
Evgesh-ka [11]

Responder:

Explicación:

Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;

T = 2Usin theta / 2

theta = 90 grados

U = 25 m / s

T = 25sin90 / 2 (9,8)

T = 25 / 19,62

T = 1,27 segundos

Por lo tanto, los cielos usarán 1.27 segundos en el aire.

La distancia horizontal es el rango;

Rango R = U√2H / g

R = 25√2 (80) /9,8

R = 25√160 / 9,8

R = 25 * √16,326

R = 25 * 4.04

R = 101,02 m

Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m

5 0
2 years ago
Someone please help me!
kirill [66]

I think it’s the first one

4 0
3 years ago
Can a body having zero velocity move with uniform speed? Give an example.
GaryK [48]
Sure. Body can move with uniform speed, and having zero velocity, when velocity becomes zero due to change in direction over time t.

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3 0
3 years ago
For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency
Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

E=hf

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For the photons in this problem,

f=6.8\cdot 10^9 Hz

So the energy of one photon is

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The number of photons contained in 1.0 mol is

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E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J

3 0
3 years ago
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