A man standing in an elevator holds a spring scale with a load of 5 kg suspended from it. What would be the reading of the scale
, if the elevator is accelerating downward with an acceleration 3.8 m/s?.
1 answer:
Answer:
3.1 kg
Explanation:
Applying,
R = m(g-a)..................... Equation 1
Where R = weight of the scale when the elevator is coming down, a = acceleration of the elevator, g = acceleration due to gravith.
From the question,
Given: m = 5 kg, a = 3.8 m/s²
Constant: g = 9.8 m/s²
Substitute these values into equation 1
R = 5(9.8-3.8)
R = 5(6)
R = 30 N
Hence the spring scale is
m' = R/g
m' = 30/9.8
m' = 3.1 kg
You might be interested in
Answer:
Explanation:
Here as we know that total angular momentum is always conserved for child + round system
so here by angular momentum conservation we have
here we have
(inertia of boy)
now we have
Answer:
The unit for power is the Watt
Weathering, Erosion, deposition, acid rain, precipitation
Explanation:
Answer:
Height, mass, acceleration.
Explanation:
I hope it helps u dear! ^_^
Answer:
h = 36.4 cm
Explanation:
given,
spring constant = 2.5 x 10⁴ N/m
compressed distance = 11.2 cm = 0.112 m
mass of the child = 44 kg
maximum height = ?
by energy of conservation
h = 0.364 m
h = 36.4 cm
