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professor190 [17]
3 years ago
13

Two pucks of equal mass collide. One puck (puck A) is stationary before the collision. After the collision the puck that was ini

tially stationary moves along in the same direction in which the puck that hit it (puck B) was initially moving. Which of the following statements is correct if the total energy of the system is conserved during the collision (elastic collision)?
A. The puck B rebounds.

B. There isn’t enough information to answer the question.

C. Both pucks slide past the point of collision.

D. The puck B remains at the point of collision.
Physics
2 answers:
miskamm [114]3 years ago
5 0

Answer:

The answer is: D. The puck B remains at the point of collision.

Explanation:

Please look at the solution in the attached Word file.

Download docx
Virty [35]3 years ago
3 0

Answer:D

Explanation:

Given

initial velocity of puck A is u_a=0

initial velocity of Puck B is u_b

After collision Puck A started moving in the direction of B and collision is elastic so Puck B remains at the point of collision and Puck A moves with initial velocity of B.

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Answer: Electromagnetic waves are generated by moving electrons. An electron generates an electric field which we can visualize as lines radiating from the electron Figure 10a. If the electron moves, say it vibrates back and forth, then this motion will be transferred to the field lines and they will become wavy Figure 10b.
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2 years ago
A wave is a disturbance that carries from one place to another through matter of space
krok68 [10]

There's supposed to be a blank in the statement, where the answer is supposed to be inserted.

The question is supposed to say: "A wave is a disturbance that carries ______ from one place to another through matter or space".

To answer the question, write the word "<em>energy</em>" in the blank.

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2 years ago
an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per seco
Semenov [28]

Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

a_c = \frac{v^2}{r}

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

a_c = \frac{(12\ m/s)^2}{2\ m}

<u>ac = 72 m/s²</u>

<u></u>

Now, the centripetal force applied by the athlete on the hammer will be:

F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)

<u>Fc = 504 N</u>

6 0
2 years ago
15. What is a thermograph?
Genrish500 [490]

Answer: A device that uses infrared sensors.

Explanation:

8 0
3 years ago
Read 2 more answers
Parallel rays of monochromatic light with wavelength 571nm illuminate two identical slits and produce an interference pattern on
Natasha2012 [34]

Answer:

8.8\times 10^{-6} W/m^2

Explanation:

We are given that

Wavelength,\lambda=571 nm=571\times 10^{-9} m

1 nm=10^{-9} m

R=75 cm=\frac{75}{100}=0.75 m

1 m=100 cm

d=0.640 mm=0.64\times 10^{-3} m

1 mm=10^{-3} m

a=0.434 mm=0.434\times 10^{-3} m

y=0.830 mm=0.830\times 10^{-3} m

I_0=5.00\times 10^{-4}W/m^2

tan\theta=\frac{y}{R}

\theta=\frac{0.830\times 10^{-3}}{0.75\times 10^{-2}}

\theta=1.1\times 10^{-3}rad

tan\theta\approx \theta

Because \theta is small.

\phi=\frac{2\pi dsin\theta}{\lambda}

\sin\theta\approx \theta,

Therefore

\phi=\frac{2\times\pi\times 0.64\times 10^{-3}\times 1.1\times 10^{-3}}{571\times 10^{-9}}

\phi=7.74 rad

\beta=\frac{2\pi a\theta}{\lambda}

\beta=5.3 rad

I=I_0cos^2(\frac{\phi}{2})(\frac{sin\frac{\beta}{2}}{\frac{\beta}{2}})^2

I=5\times 10^{-4}cos^2(\frac{7.74}{2})(\frac{sin\frac{5.3}{2}}{\frac{5.3}{2}})^2

I=8.8\times 10^{-6} W/m^2

6 0
3 years ago
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