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bezimeni [28]
3 years ago
5

If a 70 kg man is standing on the surface of the earth, then what is his weight on the moon

Physics
1 answer:
77julia77 [94]3 years ago
5 0

Answer:

P = 113.4 N

Explanation:

We know that if it is on the Moon it has another gravity. Therefore, it is known through the International System that the gravity of the Moon is 1.62 m/s², so..

Data:

  • m = 70 kg
  • g = 1.62 m/s²
  • P = ?

Use formula:

  • \boxed{\bold{P=m*g}}

Replace and solve:

  • \boxed{\bold{P=70\ kg*1.62\frac{m}{s^{2}}}}
  • \boxed{\boxed{\bold{P=113.4\ N}}}

The man's weight is <u>113.4 Newtons.</u>

Greetings.

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The bob (weight) at the end of a pendulum has a mass of 0.3 kilograms. The bob is pulled to position B and allowed to swing. It
Ivahew [28]

Answer:

0.147 J

Explanation:

The total energy that has been transformed into thermal energy is equal to the loss of gravitational potential energy between the initial situation (bob at h=0.5 m above the ground) and the final situation (bob back but at h=0.45 m above the ground).

Therefore, we have

E_{thermal}=\Delta U=mgh_1 - mgh_2 = mg(h_1 -h_2)

where

m = 0.3 kg is the mass of the bob

g = 9.8 m/s^2

h1 = 0.5 m is the initial height

h2 = 0.45 m is the final height

Substituting, we find the thermal energy

E_{thermal}=(0.3 kg)(9.8 m/s^2)(0.5 m-0.45 m)=0.147 J

Therefore, the energy transformed into thermal energy is 0.147 J.

3 0
3 years ago
A camera gives a proper exposure when set to a shutter speed of 1/250 s at f-number F8.0. The photographer wants to change the s
Oksana_A [137]

Answer:

F4.0

Explanation:

To obtain a shutter speed of 1/1000 s to avoid any blur motion the f-number should be changed to F4.0 because the light intensity goes up by a factor of 2 when the f-number is decreased by the square root of 2.

5 0
3 years ago
Light my fire! Mix me with cerium and we’ll make beautiful mischmetal together!
Vika [28.1K]

Answer:HAHAHAHHAHHA

Explanation:

7 0
3 years ago
Read 2 more answers
A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to
aksik [14]

Answer:

The answer is below

Explanation:

a) The vertical displacement = Δy = 21.5 m - 1.5 m = 20 m

The horizontal displacement = Δx = 69 m wide

Using the formula:

\Delta y = u_yt+ \frac{1}{2}a_yt^2\\ \\u_y=initial\ velocity\ of \ car\ in\ y\ direction = 0,a_y=g=acceleration\ due\ to\ gravity\\=10m/s^2\\\\\Delta y =  \frac{1}{2}a_yt^2\\\\\Delta y=\frac{1}{2}a_yt^2\\\\t=\sqrt{\frac{2\Delta y}{a_y} }=\sqrt{\frac{2*20}{10} }  =2\ m/s

Also:

\Delta x = u_xt+ \frac{1}{2}a_xt^2\\ \\u_x=initial\ velocity\ of \ car\ in\ x\ direction = 0,a_x=acceleration=0\\\\\Delta x =  u_xt\\\\u_x=\frac{\Delta x}{t}=\frac{69}{2} =34.5\ m/s

b)The car is moving at a constant speed in the horizontal direction, hence the initial velocity = final velocity

v_x=u_x=34.5\ m/s\\\\v_y=u_y+a_yt\\\\v_y=0+gt\\\\v_y=10(2)=20\ m/s\\\\v=\sqrt{v_x^2+v_y^2}=\sqrt{34.5^2+20^2}=39.9\ m/s\\ v=39.9\ m/s

4 0
3 years ago
2. Find the velocity when the displacement is 40 m and the time is 5 s.
LenKa [72]

Answer:

V=?

S= 40m

t=5s

V=S/t

V=40/5

V=8m/s

3 0
3 years ago
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