Can someone please answer this and if you dont know dont answer (:

Chemistry

2 answers:

anyanavicka [17]3 years ago

8 0

Answer: 1- Alkali metals

2- Noble gases

3- Halogens

Explanation:

Softa [21]3 years ago

8 0

Answer:

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Explanation:

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frosja888 [35]

(4) Zirconium
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8 0

3 years ago

In this reaction: Mg (s) + I₂ (s) → MgI₂ (s) If 2.68 moles of Mg react with 3.56 moles of I₂, and 1.76 moles of MgI₂ form, what

melomori [17]

Answer:

$Y=65.7\%$

Explanation:

Hello,

In this case, for the given chemical reaction, we first identify the limiting reactant by noticing that due to the 1:1 mole ratio for magnesium to iodine the reacting moles must the same, nevertheless, there are only 2.68 moles of magnesium versus 3.56 moles of iodine, for that reason, magnesium is the limiting reactant, so the theoretical turns out:

$n_{MgI_2}^{theoretical}=2.68molMg*\frac{1molMgI_2}{1molMg} =2.68molMgI_2$