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3 years ago

A 2.8-kg pile of aluminum (rho = 2.70 g/cm3) cans is melted, then cooled into a solid cube. What is the volume of the cube?

Chemistry

1 answer:

k0ka [10]3 years ago

8 0

Answer:

Explanation:

mass of aluminum 2.8 kg = 2.8 x 1000 = 2800 g

ρ = density of aluminum given = 2.7 g / cm³

density = mass / volume

volume = mass / density

= 2800 / 2.7

= 1037 cm³

So volume of cube required = 1037 cm³.

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Convert 3.30 g of copper (II) hydroxide Cu(OH)2 to molecules.

ratelena [41]

Answer:

0.18× 10²³ molecules

Explanation:

Given data:

Mass of copper hydroxide = 3.30 g

Number of molecules = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 3.30 g/97.56 g/mol

Number of moles = 0.03 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.03 mol × 6.022 × 10²³ molecules / 1mol

0.18× 10²³ molecules

6 0

2 years ago

A serving of Cheez-Its releases 1.30 x 10^4 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy we

kondor19780726 [428]

Answer:

The final temperature is:- 7428571463.57 °C

Explanation:

The expression for the calculation of heat is shown below as:-

$Q=m\times C\times \Delta T$

Where,

$Q$ is the heat absorbed/released

m is the mass

C is the specific heat capacity

$\Delta T$ is the temperature change

Thus, given that:-

Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)

Specific heat of water = 4.18 J/g°C

Initial temperature = 35 °C

Final temperature = x °C

$\Delta T=(x-35)\ ^0C/tex]
Q = [tex]1.3\times 10^4$ kcal

Also, 1 kcal = 4.18 kJ = $4.18\times 10^3$ J

So, Q = $1.3\times 10^4\times 4.18\times 10^3$ J = 54340000 J

So,

$54340000=0.00175\times 4.18\times (x-35)$

$0.00175\times \:4.18\left(x-35\right)=54340000$

$x-35=\frac{54340000}{0.007315}$

$x=7428571463.57$

Thus, the final temperature is:- 7428571463.57 °C

3 0

3 years ago

If a sample of oxygen occupies a volume of 2.15 L at a pressure of 58.0 kPa and a temperature of 25°C, what volume would this sa

Anna35 [415]

The answer is A) 1.13 L

8 0

3 years ago

Help help help pls pls pls

Arlecino [84]

Explanation:

Aluminium and Chlorine.

Al and Cl2.

4 0

3 years ago

I don't need to know why i just want the awnser

Lubov Fominskaja [6]

Answer:

I remember doing this in 7th,

1. D

2. B or D, more leaning on B though

3. A

4 0

3 years ago