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Lostsunrise [7]
3 years ago
13

A 2.8-kg pile of aluminum (rho = 2.70 g/cm3) cans is melted, then cooled into a solid cube. What is the volume of the cube?

Chemistry
1 answer:
k0ka [10]3 years ago
8 0

Answer:

Explanation:

mass of aluminum 2.8 kg = 2.8 x 1000 = 2800 g

ρ = density of aluminum given = 2.7 g / cm³

density = mass / volume

volume = mass / density

= 2800 / 2.7

= 1037 cm³

So volume of cube required = 1037 cm³.

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The action or process of making a copy of something.
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3 years ago
If Log 4 (x) = 12, then log 2 (x / 4) is equal to
Alexus [3.1K]

The value of log₂(x/4) is 22. Using the properties of the logarithm, the required value is calculated.

<h3>What are the required properties of the logarithm?</h3>

The required logarithm properties are

logₐx = n ⇒ aⁿ = x; and logₐ(xⁿ) = n logₐ(x);

Where a is the base of the logarithm.

<h3>Calculation:</h3>

It is given that,

log₄(x) = 12;

On applying the property logₐx = n ⇒ aⁿ = x; here a = 4;

So,

log₄(x) = 12 ⇒ 4¹² = x

⇒ x = (2²)¹² = 2²⁴

Then, calculating log₂(x/4):

log₂(x/4) = log₂(2²⁴/4)

              = log₂(2²⁴/2²)

              = log₂(2²⁴ ⁻ ²)

              = log₂(2²²)

On applying the property logₐ(xⁿ) = n logₐ(x);

log₂(x/4) = 22 log₂2

We know that logₐa = 1;

So,

log₂(x/4) = 22(1)

∴ log₂(x/4) = 22.

Learn more about the properties of logarithm here:

brainly.com/question/12049968

#SPJ9

8 0
1 year ago
Convert 72 hours to seconds
AfilCa [17]

Answer:

259,200

Explanation:

3 0
2 years ago
Compound is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about. In the solid state it does not
son4ous [18]

Answer:

Compound 3 is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about −10°C. In the solid state it does not conduct electricity. ... It dissolves slightly in water, and a solution of 2g in 100mL of water doesn't change the electrical conductivity of the water.

5 0
2 years ago
Can someone help me? It needs to have a diagram that has arrows.
daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)

The expression for enthalpy change is,

\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]

Putting the values we get :

\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]

-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]

H_f_{C_4H_{10}=-125kJ/mol

Thus enthalpy change for formation of butane is -125 kJ/mol

5 0
3 years ago
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