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pogonyaev
2 years ago
15

2. What are the 3 types of matter?

Physics
1 answer:
Lapatulllka [165]2 years ago
8 0

Answer:

the three types of matter are solid, liquid, gas

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PLEASE HELP WILL GIVE BRAINLIEST!
Igoryamba

C. FM radio waves is the answer.

6 0
3 years ago
A football player is running with a velocity or 10 m/s. At that velocity, his momentum is 2500 kg*m/s. What is the football play
DedPeter [7]

The mass of the football player is 250 kg.

<u>Explanation:</u>

Momentum is defined as the product of mass and velocity. So here the velocity (v) is given as 10 m/s and the momentum is given as 2500 kg m /s. So we can determine the mass (m) of the player by substituting the known terms in the formula of determining momentum as shown below.

             \text {Momentum}(p)=m \times v

As we know the value of momentum and velocity, the mass can be found as,

             m=\frac{p}{v}=\frac{2500}{10}=250 \mathrm{kg}

Thus, the mass of the football player is found to be 250 kg.

7 0
3 years ago
In----- theory, the actual wishes that are threatening to the dreamers conscious awareness are disguised
Mandarinka [93]

Answer:

Unconscious wish fulfillment

Explanation:

Unconscious wish fulfillment

(In the unconscious wish fulfillment theory, the actual wishes of the dreamer that are threatening to the dreamer's conscious awareness are disguised.)

7 0
3 years ago
Lasers are classified according to the eye-damage danger they pose. Class 2 lasers, including many laser pointers, produce visib
Alexus [3.1K]

Answer:

<em>a) 318.2 W/m^2</em>

<em>b) 2.5 x 10^-4 J</em>

<em>c) 1.55 x 10^-8 v/m</em>

<em></em>

Explanation:

Power of laser P = 1 mW = 1 x 10^-3 W

exposure time t = 250 ms = 250 x 10^-3 s

If beam diameter = 2 mm = 2 x 10^-3 m

then

cross-sectional area of beam A = \pi d^{2} /4 = (3.142 x (2*10^{-3} )^{2})/4

A = 3.142 x 10^-6 m^2

a) Intensity I = P/A

where P is the power of the laser

A is the cros-sectional area of the beam

I = ( 1 x 10^-3)/(3.142 x 10^-6) = <em>318.2 W/m^2</em>

<em></em>

b) Total energy delivered E = Pt

where P is the power of the beam

t is the exposure time

E = 1 x 10^-3 x 250 x 10^-3 = <em>2.5 x 10^-4 J</em>

<em></em>

c) The peak electric field is given as

E = \sqrt{2I/ce_{0} }

where I is the intensity of the beam

E is the electric field

c is the speed of light = 3 x 10^8 m/s

e_{0} = 8.85 x 10^9 m kg s^-2 A^-2

E = \sqrt{2*318.2/3*10^8*8.85*10^9}  = <em>1.55 x 10^-8 v/m</em>

6 0
3 years ago
Slow-twitch muscles are needed for what?
Tresset [83]
Slow-twitch muscles<span> help enable long-endurance feats such as distance running, while fast-</span>twitch muscles<span> fatigue faster but are used in powerful bursts of movements like sprinting. Hope that this can help!!!</span>
8 0
3 years ago
Read 2 more answers
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