Answer:
water sample have more water content
Explanation:
given data
soil 1 is saturated with water
unit weight of water = 1 g/cm³
soil 2 is saturated with alcohol
unit weight of alcohol = 0.8 g/cm³
solution
we get here water content that is express as
water content = ....................1
here soil is full saturated so is 100% in both case
so put here value for water
water content = 100 % × 1
water content = 1 g
and
now we get for alcohol that is
water content = 100 % × 0.8
water content = 0.8 g
so here water sample have more water content
Answer:
a) the actual thermal efficiency is 15.17%
b) the maximum thermal efficiency is 29.55%
Explanation:
a) the actual thermal efficiency is for a heat engine is,
E actual = Power obtained / Necessary heat rate as input = P/q
q = F * c * (Tinitial - Tfinal) , F = mass flow rate , c=specific heat of water ( we assume c= 1 cal/gr°C = 4.186 J/gr°C= 4.186 kJ/kg°C)
q = 210 Kg/s * 4.186 kJ/kg°C (150°C - 90 °C) = 52743.6 kW
therefore
E actual = 8000 kW /52743.6 kW = 0.1517 = 15.17%
b) the maximum thermal efficiency for the same heat source and heat sink corresponds to the one of a Carnot engine. Where,
E max = 1 - Tc/Th , Th is the absolute temperature of the hot heat source and Tc is the absolute temperature of the cold heat sink.
therefore
Th= 150°C + 273 °C = 423 K
Tc= 25°C + 273°C = 298 K
thus
E max = 1- 298/423 = 0.2955 = 29.55%
(a) The thermal efficiency of the cycle.
The thermal efficiency of the cycle is given by
NThermal= net work/ heat supplied
NThermal= WNet/QH
=2026.08/4547.82= 44.55%
(b) The backwork ratio:
compressor work/ turbine work
=1760.76/3786.84= 0.465
(c) The net power developed:
WNet= WT-WC
WNet= 3786.84- 1760.76= 2026.08 kW
The heat transferred to and the work produced by the steam during this process is 13781.618 kJ/kg
<h3>
How to calcultae the heat?</h3>
The Net Change in Enthalpy will be:
= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg
Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)
= 1/2 x ( 75 + 225) x (5 - 2)
W = 450 KJ
From the First Law of Thermodynamics, Q = U + W
So, Heat Transfer = Change in Internal Energy + Work Done
= 13331.618 + 450
Q = 13781.618 kJ/kg
Learn more about heat on:
brainly.com/question/13439286
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