I think the answer would be 1.58 g.
Answer:
the reaction is spontaneous at T > 2900 K
Explanation:
∴ ΔH = +120 KJ
∴ ΔS = (-42 J/K)*(KJ/1000 J) = -0.042 KJ/K
∴ ΔG < 0 ⇒ the reaction is spontaneous
⇒ at T = 2900 K:
⇒ ΔG = 120 - (2900)(-0.042) = 120 - 121.8 = - 1.8 KJ < 0
Answer:
12.9
Explanation:
From the question given, the concentration of the hydroxide ion is given:
[OH^-] = 1.4 x 10^ -13M
pOH =?
pOH = —Log [OH^-]
pOH = —Log 1.4 x 10^ -13
pOH = 12.9
