Answer:
it is answer of u are question
HELP PLSSSSSSS ASAP FIRST CORRECT ANSWER WILL GET BRANLIST. A bunny accidentally knocks a basket of eggs off of a table. Luckily
2 answers:
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Answer:
No he should not attempt the pass
Explanation:
Let t be the time it takes for the car to pass the truck. The driver should ONLY attempt to pass when the distance covered by himself plus the distance covered by the oncoming car is less than or equal 400 m (a near miss)
At acceleration of 1m/s2 and a clear distance of 10 + 20 + 10 = 40 m, we can use the following equation of motion to estimate the time t in seconds
Within this time frame, the first car would have traveled a total distance of the clear distance (40m) plus the distance run by the truck, which is
8.94 * 25 = 223.6m
So the total distance traveled by the first car is 223.6 + 40 = 263.6m
The distance traveled by the 2nd car within 8.94 s at rate of 25m/s is
8.94 * 25 = 223.6 m
So the total distance covered by both cars within this time frame
223.6 + 263.6 = 487.2m > 400 m
So no, he should not attempt the pass as we will not clear it in time.
Answer:
The loss in rotational kinetic energy due to the collision is 36.585 J.
Explanation:
Given;
mass of the disk, m₁ = 1.64 kg
radius of the disk, r = 0. 61 m
angular velocity of the disk, ω₁ = 17.6 rad/s
mass of the rod, m₂ = 1.51 kg
length of the rod, L = 1.79 m
angular velocity of the rod, ω₂ = 5.12 rad/s (clock-wise)
let the counter-clockwise be the positive direction
let the clock-wise be the negative direction
The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;
m₁ω₁ + m₂ω₂ = ωf(m₁ + m₂)
where;
ωf is the common final angular velocity
1.64 x 17.6 + 1.51(-5.12) = ωf(1.64 + 1.51)
21.1328 = ωf(3.15)
ωf = 21.1328 / 3.15
ωf = 6.709 rad/s
The moment of inertia of the disk is calculated as follows;
The moment of inertia of the rod about its center is calculated as follows;
The initial rotational kinetic energy of the disk and rod;
The final rotational kinetic energy of the disk-rod system is calculated as follows;
The loss in rotational kinetic energy due to the collision is calculated as follows;
Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.