Answer:
1) = 8721 Kg*m/s
2) = 12450 Kg*m/s
3) θ = 55.03°
4) P = 15182 Kg*m/s
5) V = 8.91 m/s
6)
145099.5 J > 67638 J
Explanation:
1) The momentum is calculated by the next equation:
P = MV
where M is the mass and V is the velocity
so, the linear momentum of the car is:
= (459)(19)
= 8721 Kg*m/s
2) the linear momentum of the truck is:
= (1245)(10)
= 12450 Kg*m/s
3) For answer this we will use the law of the conservation of the linear momentum where:
:
So, we will do this for each axis:
First on axis x:
Where is the mass of the blue car, is the velocity of the car, is the velocity of the system in x after the collition and is the mass of both cars. Replacing, we get:
Solving for :
Second, on axis y:
Where is the mass of the truck, is the velocity of the truck, is the velocity of the system in y after the collition and is the mass of both cars.
Solving for :
Now using the definition of tangent:
θ =
θ = 55.03°
4) First, we have to find the magnitude of the velocity using the pythagorean theorem as:
V =
V = 8.91 m/s
With the velocity, we find the momentum as:
P = MV
P =(1245+459)(8.91)
P = 15182 Kg*m/s
5) This was calculated before, so:
V = 8.91 m/s
6) The energy of the total system before the collision is calculated as:
The energy of the total system after the collision is calculated as:
So, the energy of the system before the collision is bigger than the energy of the system after the collision.