1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lianna [129]
2 years ago
5

If the heat of combustion for a specific compound is −1160.0 kJ/mol and its molar mass is 86.47 g/mol, how many grams of this co

mpound must you burn to release 541.20 kJ of heat?
Chemistry
1 answer:
notsponge [240]2 years ago
8 0

Answer:

40.34 g

Explanation:

First, we divide the heat to release by the heat of combustion to obtain the required moles of compound:

541.20 kJ/(1160.00 kJ/mol) = 0.4665 mol

So, we have to burn approximately 0.47 mol of the compound. We convert the moles to mass in grams by using the molar mass:

mass = molar mass x moles = 86.47 g/mol x 0.4665 mol = 40.34 g

Therefore, you must burn 40.34 grams of the compound to release 541.20 kJ of heat.

You might be interested in
Standard reduction potentials are based on which element?
KonstantinChe [14]
They're based on hydrogen.
6 0
3 years ago
Read 2 more answers
What is conductivity? How is it measured?
horrorfan [7]

Conductivity is a measurement of the ability of an aqueous solution to transfer an electrical current.

Explanation:

To calculate the conductivity of a solution you simply multiply the concentration of each ion in solution by its molar conductivity and charge then add these values for all ions in solution.

3 0
2 years ago
Read 2 more answers
What are the factors that affect the rate of dissolution? color, temperature, stirring texture, surface area, stirring temperatu
tangare [24]
Color, temperature, stirring
3 0
3 years ago
Read 2 more answers
Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
barxatty [35]

Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

[Cl^-]=2S

Ksp=[Pb^{2+}]\times [Cl^-]^2

Ksp=S \times (2S)^2

Ksp=4S^3

S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

4 0
3 years ago
A truck travels 110 miles and it speed is 55mi/hr. How long did it take to
hammer [34]

Answer:

2 hours Speed =110/2=55 miles ler hour

4 0
2 years ago
Other questions:
  • Iron oxide and hydrogen react to form iron and water in the following chemical equation:
    8·1 answer
  • Completely classify jet fuel.
    8·1 answer
  • Module 2 dba for chemistry questions? flvs
    6·1 answer
  • An acid is a polar substance that dissolves in water and
    9·2 answers
  • Describe how molecular motion and distance between molecules change as ice is heated to become a liquid and then a gas
    11·1 answer
  • What is the molar mass of a substance?
    8·1 answer
  • Who made the periodic table
    5·2 answers
  • What happens to the density of a box full of leaves if you crush up all the leaves and place them in another box
    11·1 answer
  • Under what conditions is a real gas closely approximated by an ideal gas?
    9·1 answer
  • Measurements show that unknown x compound has the following composition:
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!