All categories

3 years ago

A 1100 kg car starts from rest and accelerates for 5 seconds at 4.6m/s/s how much power does the car generate

Physics

1 answer:

SIZIF [17.4K]3 years ago

3 0

Answer:

The power expended by the car during the acceleration is 116.38KW

Explanation:

Power is a term that defines the rate at which energy is expended whenever work is done.

Power can be given as Force X velocity.

Force can be found using the formula:

F = mass X acceleration.

In this case,

F = 1100kg X 4.6m/s2

F = 5060 N

The final velocity, v of the car can be obtained from this formula:

v = u+ at

U = initial velocity = 0 (since the car started from rest)

a = acceleration = 4.6m/s2

t = time = 5 seconds

v = 0 + 4.6 X 5 = 23 m/s

Therefore, the power expended is 5060N X 23m/s=116,380W

The power expended by the car during the acceleration is 116.38KW

You might be interested in

An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1

Svetlanka [38]

Answer:

How far will the electron travel beforehitting a plate is 248.125mm

Explanation:

Applying Gauss' law:

Electric Field E = Charge density/epsilon nought

Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12

Therefore E = 1.0 x 10^-6/8.85× 10^-12

E= 1.13×10^5N/C

Force on electron F=qE

Where q=charge of electron=1.6×10^-19C

Therefore F=1.6×10^-19×1.13×10^5

F=1.808×10^-14N

Acceleration on electron a = Force/Mass

Where Mass of electron = 9.10938356 × 10^-31

Therefore a= 1.808×10^-14 /9.11 × 10-31

a= 1.985×10^16m/s^2

Time spent between plate = Distance/Speed

From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2

Therefore Time = 0.01/2×10^6

Time =5×10^-9s

How far the electron would travel S =ut+ at^2/2 where u=0

S= 1.985×10^16×(5×10^-9)^2/2

S=24.8125×10^-2m

S=248.125mm

4 0

3 years ago

When the voltage is at a maximum positive value, the current is at a value that is_________.

alukav5142 [94]

Answer:

When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive

Explanation:

We know that the relation between the Voltage and the current is given using the Ohm's law, which states that the voltage (V) is directly proportional to the current (I)

Mathematically,

V ∝ I

Hence,

When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive

4 0

2 years ago

Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very

timofeeve [1]

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ $v=\frac{502.1}{\sqrt{3} }$

$=289.9 \ m/s$

The time will be:

⇒ $t=\frac{d}{v}$

$=\frac{2\times 6}{289.9}$

$=\frac{12}{289.9}$

$=0.041 \ sec$

hence,

⇒ $N=\frac{1}{t}$

$=\frac{1}{0.041}$

$=24.39 \ per \ sec$

4 0

2 years ago

Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of

morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner $(v_1)$ =3.1 m/s

speed of second runner $(v_2)$ =4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner $t=\frac{295.6}{4.65}=63.56 s$

time required by first runner to reach finish line $=\frac{250}{3.1}=80.64 s$

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

3 0

3 years ago

A sled is at rest at the top of a 2 m high slope. The sled has a mass of 45 kg. The sled's potential energy isJ. (Formula: PE =

elixir [45]

Data:

h = 2m
m = 45 Kg
PE = ? (Joule)

Adopting, gravity (g) ≈ <span>9,8 m/s²
</span>
Formula: $PE_{grav} = mass * g * height$

Solving:

$PE_{grav} = mass * g * height$
$PE_{grav} = 45*9,8*2$
$PE_{grav} = 882J$

Answer:
<span>The sled's potential energy is 882 Joules</span>

8 0

2 years ago

Read 2 more answers