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valentinak56 [21]
3 years ago
5

What two processes occur at the mid ocean ridge?

Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

ridge push and slab pull

Explanation:

there are two processes through to be responsible for the spreading seen at mid ocean ridges and there is some uncertainty as to which is dominant. ridge push occurs when the weight of the ridge pushes at the rest of tectonic plate away from the ridge often towards a subduction zone. hope this helped

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Ammonium carbonate has the chemical formula (NH42CO3How many hydrogen atoms (H) are in ammonium carbonate?
Gre4nikov [31]

Answer:

8

Explanation:

there are two ammonium ions with four hydrogen atoms each.

4*2=8

6 0
3 years ago
Why does the flask have to be closed during the hydrochloric acid and sodium carbonate reaction?
Orlov [11]

Answer:

The flask has to be closed during the hydrochloric acid and sodium carbonate reaction as the resultant gas got trapped inside the closed flask.

Explanation:

The hydrochloric acid and sodium carbonate reaction was exothermic that caused the pressure to decrease. The flask has to be closed during the hydrochloric acid and sodium carbonate reaction as the resultant gas got trapped inside the closed flask.

In exothermic reactions, energy is produced in the form of heat or light.

4 0
3 years ago
help me please. Can you please explain to me how to solve them? you can also send me a photo if that's better for you. thanks al
zheka24 [161]

Refer to the attachment

7 0
3 years ago
A sample of 2.45g aluminum oxide decomposes into 1.3g of aluminum and 1.15g of oxygen. What is the percentage composition of the
Vitek1552 [10]

Answer:

%Al = 53.1%%

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Explanation:

If we know the grams of a chemical compound in a specific reaction, it is possible to know the percentage of each atom that composes it.

For the Aluminum Oxide in this problem, we know its total weight and the grams of each component.

therefore we can determine the percentage ratio of its components through:

For Al

%Al = \frac{mass of Al}{mass of Aluminium oxide} . 100%

% Al = \frac{1,3 g}{2,45 g} . 100%

%Al = 53.1%%

In the same way for oxygen

%O = \frac{mass of O}{mass of Aluminium oxide} . 100%

%O = \frac{1,5 g}{2,45 g} . 100%

%O = 46.9%

5 0
3 years ago
How many miles of carbon are needed to react with 5.44moles of so2
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The answer is 13.6 moles c
3 0
4 years ago
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