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3 years ago

What two processes occur at the mid ocean ridge?

Chemistry

1 answer:

Natasha2012 [34]3 years ago

6 0

Answer:

ridge push and slab pull

Explanation:

there are two processes through to be responsible for the spreading seen at mid ocean ridges and there is some uncertainty as to which is dominant. ridge push occurs when the weight of the ridge pushes at the rest of tectonic plate away from the ridge often towards a subduction zone. hope this helped

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Determine the concentration of an HBr solution if a 45.00 mL aliquot of the solution yields 0.5555 g AgBr when added to a soluti

amid [387]

Molecular weight of AgBr = 187.7
moles of Ag = $\frac{0.5555}{187.7} = 2.96 x 10^{-3}$
moles of Br = moles of Ag = 2.96 x 10⁻³ mol
concentration of HBr (Molarity) = conc. of Br (strong acid) = $\frac{2.96 x 10^{-3} }{45 x 10^{-3} } = 0.0658 mol/l$

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3 years ago

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A given atom has 3 protons, 4 neutrons, and 3 electrons. Describe how you can use those three values to describe the structure,

ELEN [110]

Charge # = protons - electons

Mass # = protons + neutrons

so that would be

3-3= charge#
3+4= mass#

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3 years ago

A 1.25 g gas sample occupies 663 ml at 25∘ c and 1.00 atm. what is the molar mass of the gas?

lakkis [162]

Using ideal gas equation,

$P\times V=n\times R\times T$

Here,

P denotes pressure

V denotes volume

n denotes number of moles of gas

R denotes gas constant

T denotes temperature

The values at STP will be:

P=1 atm

T=25 C+273 K =298.15K

V=663 ml=0.663L

R=0.0821 atm L mol ⁻¹

Mass of gas given=1.25 g g

Molar mass of gas given=?

$Number of moles of gas, n= \frac{Given mass of the gas}{Molar mass of the gas}$

$Number of moles of gas, n= \frac{1.25}{Molar mass of the gas}$

Putting all the values in the above equation,

$1\times 0.663=\frac{1.25}{Molar mass of the gas}\times 0.0821\times 298.15$

Molar mass of the gas=46.15

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3 years ago

C6H12O6 + 6O2 → 6CO2 + 6H2O is the chemical equation for cellular respiration. What are the products in this reaction?

maks197457 [2]

Answer:

The products are: A) CO2, H2O

Explanation:

Those products that are seen on the right side of the reaction (that is, those substances that are generated from the reagents). In this case they are carbon dioxide and water.

The general equation of cellular respiration is:

C6H1206 + 602 -> 36 ATP + 6CO2 + 6H20

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3 years ago

In the laboratory you are asked to make a 0.175 m barium iodide solution using 13.9 grams of barium iodide. How much water shoul

BARSIC [14]

<u>Answer:</u> The mass of water that should be added in 203.07 grams

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$