Question

Two out of phase loudspeakers are some distance apart. A person stands 4.50 m from one speaker and 3.80 m from the other. What is the third lowest frequency at which the person will hear constructive interference? The speed of sound in air is 347 m/s. Hz

Answer 1

Answer:

The third lowest frequency is 1489.27 Hz.

Explanation:

Given that,

Distance of person from one speaker= 4.50 m

Distance of person from the other = 3.80 m

The longest wavelength is the shortest frequency.

We need to calculate the difference between the speakers

The difference between the speakers d= 4.50-3.80 =0.7 m

We know that,

The longest wavelength is such that one wavelength

$\lambda = d$

So, The third longest wavelength is

$3\lambda=d$

Put the value of d

$\lambda=\dfrac{0.7}{3}$

$\lambda=0.233\ m$

We need to calculate the lowest frequency

Using formula of frequency

$f=\dfrac{v}{\lambda}$

$f=\dfrac{347}{0.233}$

$f=1489.27\ Hz$

Hence, The third lowest frequency is 1489.27 Hz.