2) A car going down the road has a velocity of 20 m/s. If the car continues at this

Physics

2 answers:

natima [27]3 years ago

8 0

140 u just multiply the numbers

Artemon [7]3 years ago

5 0

Answer: 140

Explanation: just multiply 7 x 20

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A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1).

KengaRu [80]

The reading on the scale is equal to the weight of the student which is 646.8 N.

The given parameters;

<em>mass of the student, m = 66 kg</em>

The reading on the scale is determined by applying Newton's second law of motion as follows;

$R = ma+ mg\\\\R = m(a + g)\\\\R = m(0 + g)\\\\R = mg$

<em>The student is at rest and not accelerating, a =0</em>

$R = 66 \times 9.8\\\\R = 646.8 \ N$

Thus, the reading on the scale is equal to the weight of the student which is 646.8 N.

The complete question is below:

A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1). what is the reading on the scale?

Learn more about Newton's second law here: brainly.com/question/3999427

3 0

2 years ago

sandra is riding a bice at 10.0 meters/second. she slows down to 2.0 meters/second in 10 seconds. her acceleration is blank mete

MrRa [10]

Explanation:

$a = \frac{v - v _{i} }{t}$

Her intial velocity is 10

Her final velocity is 2

Time is 10 seconds.

$a = \frac{2 - 10}{10}$

$a = - \frac{4}{5}$

8 0

1 year ago

Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w

PtichkaEL [24]

Answer:

yes it will be louder sound than he use only one speaker

so he must have to move towards left speaker by distance 0.125 m

Explanation:

As we know that the two speakers are coherent source of sound

So here we can say that the sound received from the two sources will give maximum intensity when path difference of the source is integral multiple of the wavelength of the sound

While if we receive minimum intensity of sound then the path difference from each source must be odd multiple of half the wavelength of sound.

so here we know that

$wavelength = \frac{speed}{frequency}$