The correct answer is A. An element cannot be separated into simpler substances or converted into another substance by chemical processes. Elements are the most simplest form of the chemicals. They are what we see in the periodic table.
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Mass defect and binding energy are related as
ΔE = Δmc^2
Where
ΔE = binding energy
Δm = mass defect
c = speed of light
given
mass defect = 3.09x 10-27 kg
We know that speed of light = 3 X 10^8 m /s
ΔE = 3.09x 10-27 kg (3 X 10^8 m /s)^2 = 2.781 X 10^-10 J / Kg
.
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This dissociation occur because:
O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).
K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.
that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.
The rate law for the reaction : r=k.[A]²
<h3>Further explanation</h3>
Given
Reaction
A ⟶ B + C
Required
The rate law
Solution
The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants
For the second-order reaction it can be:
1. the square of the concentration of one reactant.
![\tt r=k[A]^2](https://tex.z-dn.net/?f=%5Ctt%20r%3Dk%5BA%5D%5E2)
2. the product of the concentrations of two reactants.
![\tt r=k[A][B]](https://tex.z-dn.net/?f=%5Ctt%20r%3Dk%5BA%5D%5BB%5D)
And the reaction should be(for second order) :
2A ⟶ B + C
Thus, for reaction above (reactant consumption rate) :
![\tt r=-\dfrac{\Delta A}{2\Delta t}=k[A]^2](https://tex.z-dn.net/?f=%5Ctt%20r%3D-%5Cdfrac%7B%5CDelta%20A%7D%7B2%5CDelta%20t%7D%3Dk%5BA%5D%5E2)
Answer:
pH = 4.09
Explanation:
molarity of oxalic acid in the solution
= 0.1 x 25 / (25 + 35)
= 0.0417 M
molarity of NaOH in the solution
= 0.1 x 35 / (25 +35)
= 0.0583 M
H2C2O4 + NaOH -------------------> NaHC2O4 + H2O
0.0417 0.0583 0 0
0 0.0166 0.0417
now second acid -base titration
NaHC2O4 + NaOH -------------------> Na2C2O4 + H2O
0.0417 0.0166 0 0
0.0251 0 0.0166 ---
now
pH = pKa2 + log [Na2C2O4 / NaHC2O4]
pH = 4.27 + log (0.0166 / 0.0251)
pH = 4.09