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atroni [7]
3 years ago
10

How do I find the hydrated formula?

Chemistry
1 answer:
Nady [450]3 years ago
4 0

Answer:

In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation

Explanation:

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Select the correct answer.
Gennadij [26K]

The correct answer is A. An element cannot be separated into simpler substances or converted into another substance by chemical processes. Elements are the most simplest form of the chemicals. They are what we see in the periodic table.

Please mark brainliest. :)

8 0
3 years ago
kilograms represented by the mass defect for thorium -234=3.09x 10-27 kg what is the nuclear binding energy for thorium -234
Dafna1 [17]

Mass defect and binding energy are related as

ΔE = Δmc^2

Where

ΔE = binding energy

Δm = mass defect

c = speed of light

given

mass defect = 3.09x 10-27 kg

We know that speed of light = 3 X 10^8 m /s

ΔE = 3.09x 10-27 kg  (3 X 10^8 m /s)^2 = 2.781 X 10^-10 J / Kg

.

.

4 0
3 years ago
Read 2 more answers
When KCl dissolves in water:
34kurt

This dissociation occur because:

O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).

K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.

that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.

3 0
3 years ago
Multiple choice-- please help!
kvasek [131]

The rate law for the reaction : r=k.[A]²

<h3>Further explanation</h3>

Given

Reaction

A ⟶ B + C

Required

The rate law

Solution

The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants

For the second-order reaction it can be:

1. the square of the concentration of one reactant.

\tt r=k[A]^2

2. the product of the concentrations of two reactants.

\tt r=k[A][B]

And the reaction should be(for second order) :

2A ⟶ B + C

Thus, for reaction above (reactant consumption rate) :

\tt r=-\dfrac{\Delta A}{2\Delta t}=k[A]^2

6 0
3 years ago
A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution i
____ [38]

Answer:

pH = 4.09

Explanation:

molarity of oxalic acid in the solution

         = 0.1 x 25 / (25 + 35)

         = 0.0417 M

molarity of NaOH in the solution

          = 0.1 x 35 / (25 +35)

         = 0.0583 M

H2C2O4 + NaOH -------------------> NaHC2O4 + H2O

0.0417          0.0583                            0                0

0                      0.0166                         0.0417

now second acid -base titration  

NaHC2O4 + NaOH -------------------> Na2C2O4 + H2O

0.0417             0.0166                              0                0

0.0251                 0                                  0.0166         ---

now

pH = pKa2 + log [Na2C2O4 / NaHC2O4]

pH = 4.27 + log (0.0166 / 0.0251)

pH = 4.09

3 0
3 years ago
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