Answer:
N2(g) + 3H2-> 2NH3(g) This is the balanced equation
Note the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2 This will be important.
moles N2 present = 28.0 g N2 x 1 mole N2/28 g = 1 mole N2 present
moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present
Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2.
moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced
grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced
NOTE: The key to this problem is recognizing that N2 is limiting, and therefore limits how much NH3 can be produced.
Explanation:
I ready is easy just read the passage the answer is right there if you just read
Explanation:
Mass ratio C : H : N = 27.3 : 9.10 : 63.6
Mole ratio C : H : N = 27.3/12: 9.10/1 : 63.6/14
( Divide the mass ratio by their molar masses to find the ratio between moles)
Mole ratio = 2.275 : 9.10 : 4.54
= 2.275/2.275 : 9.10/2.275 : 4.54/2.275
= 1 : 4 : 2
Answer is CH4N2
Answer:
The water molecules begin to move faster, than eventually the water turns into vapor.
Explanation: