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kati45 [8]
3 years ago
12

How would the intensity of light from the bulb change if you were to: a) Dissolve some additional CuSO4(s) in the CuSO4 solution

?
Chemistry
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

The intensity of the light bulb increases

Explanation:

The conductivity of a solution depends on the concentration of ions in solution. This implies that, if the concentration of ions in solution is increased, the conductivity of the solution increases accordingly.

If we add more CuSO4(s) to the CuSO4 solution, the concentration of ions in the solution and consequently the conductivity of the solution increases.

Therefore, the intensity of the light bulb increases.

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The enthalpy change for converting 1.00 mol of ice at -25.0 ∘c to water at 90.0∘c is ________ kj. the specific heats of ice, wat
liubo4ka [24]

Answer : The enthalpy change for converting 1 mole of ice at -25.0^oC to water at 90^oC is, 7.712 KJ

Solution :

Process involved in the calculation of enthalpy change :

(1):ice(-25^oC)\rightarrow ice(0^oC)\\\\(2):ice(0^oC)\rightarrow water(0^oC)\\\\(3):water(0^oC)\rightarrow water(90^oC)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{ice}\times (T_2-T_1)]+\Delta H_{fusion}+[m\times c_{water}\times (T_3-T_2)]

where,

\Delta H = enthalpy change

m = mass of water = 1mole\times 18g/mole=18g

c_{ice} = specific heat of ice = 2.09 J/gk

c_{water} = specific heat of water = 4.18 J/gk

\Delta H_{fusion} = enthalpy change for fusion = 6.01 KJ/mole = 0.00601 J/mole

conversion : 0^oC=273k

T_1 = initial temperature of ice = 0^oC=273k

T_2 = final temperature of ice = -25^oC=273+(-25)=248k

T_3 = initial temperature of water = 0^oC=273k

T_4 = final temperature of water = 90^oC=273+90=363k

Now put all the given values in the above expression, we get

\Delta H=[18g\times 2.09J/gK\times (273-248)k]+0.00601J+[18g\times 4.18J/gK\times (363-273)k]

\Delta H=7712.106J=7.712KJ     (1 KJ = 1000 J)

Therefore, the enthalpy change for converting 1 mole of ice at -25.0^oC to water at 90^oC is, 7.712 KJ

3 0
3 years ago
At the _______ point of a substance, the particles have enough kinetic energy to break free from their fixed positions.
Natasha_Volkova [10]

Answer:

At the nucleus point of a substance, the particles have enough kinetic energy to break free from their fixed positions.

Answer : nucleus

5 0
2 years ago
What properties you can observe or measure?
Advocard [28]
We can observe physical properties of elements and compounds without changing the substance.

Examples of physical properties: Density, color, boiling point, state of matter, appearance: dull or shiny, etc. 

But we can also observe and measure chemical properties by reacting a substance with something else. For example, like mixing baking soda and vinegar together. The vinegar reacts with the baking soda and produces carbon dioxide: a new substance. 

Some examples of chemical properties: Flammability, amount of heat that is released during combustion, toxicity (how much damage it causes to other organisms), radioactivity, and ability to oxidize (when you have metal that becomes rusty looking).
4 0
4 years ago
When two amino acids condense to form a dipeptide, what is the other product of the reaction? enter the molecular formula?
Viktor [21]
When amino acids are linked together, they form a peptide bond. When it joins two amino acids, it forms a dipeptide bond. When a long chain of amino acids are joined by peptide bonds, it becomes a protein. As shown in the picture, it loses H-OH molecules. So, it will appear in the product side as a H₂O molecule.

3 0
4 years ago
Does alcohol affect enveloped or naked viruses more
slega [8]

Answer:

the protein capsid of naked  viruses is less susceptible to environmental .  condition

Explanation:

because the envelop is made in part of phospholipids. once the envelop is lysed ,the virus loses its functiovnal receptors and still able to infect susceptible cells.

7 0
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