Answer : The equilibrium concentration of is, 0.16 M
Explanation :
First we have to calculate the concentration of
and,
The given chemical reaction is:
Initial conc. 0.4 2.0 0
At eqm. (0.4-x) (2.0+x) x
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = -5.57 and x = 0.24
We are neglecting the value of x = -5.57 because equilibrium concentration can not be more than initial concentration.
Thus, the value of x = 0.24
The equilibrium concentration of = (0.4-x) = (0.4-0.24) = 0.16 M
Therefore, the equilibrium concentration of is, 0.16 M
Answer:48kg of SiO2, 0.5kg of Al2O3, and 1.5kg of B2O3
Will be the final product
Explanation:
I) 96wt% of SiO2 will amount to 96/100*50 = 0.96*50=48kg of SiO2
ii) 1wt% of Al2O3 will amount to 1/100*50 = 0.01*50=0.5kg of Al2O3
III) 3wt% of B2O3 will amount to 3/100*50 = 0.03*50=1.5kg of B2O3..
The overall product form 48+ 0.5+1.5= 50kg
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