The balanced reaction is given as:
<span>2Ca(s)+O2(g)→2CaO(s)
</span>
We are given the amount of oxygen gas to be used for the reaction. This will be the starting point of our calculations.
0.016 mol O2 ( 2 mol CaO / 1 mol O2 ) = 0.032 mol CaO
<span>Therefore, for the reaction, the amount of calcium oxide produced is 0.032 moles.</span>
I₂ is the halogens which is darkest in colour than other.
<h3>What is halogen? </h3>
Halogens are the elements which belongs to group 17. Group 17 elements are known as halogens. They are highly electronegative in nature.
The last electronic configuration is ns2 np5. Since, one electron is less to get stable electronic configuration. Therefore, they accept one electron and get stable electronic configuration.
<h3>Why halogens are dark in colour? </h3>
As we move down the group, the darkness of colour increases. This is due to ionization energy which decreases as we move down the group. This is due to increase in the atomic size and decrease in nuclear form which further make high energy level to absorb lesser light and reflects deepen colour on moving down the group. Due to which they appears dark. Therefore, option A is the correct option.
Thus, we can concluded that I₂ is the halogens which is darkest in colour than other.
learn more about Halogens:
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Answer:
Nitrogen (N2) are not compounds because each is composed of a single element.
<u>Answer:</u> The percentage abundance of
and
isotopes are 75.77% and 24.23% respectively
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of
isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of
isotope = 62.9396 amu
Fractional abundance of
isotope = x
- <u>For
isotope:</u>
Mass of
isotope = 64.9278 amu
Fractional abundance of
isotope = 1 - x
- Average atomic mass of copper = 63.546 amu
Putting values in equation 1, we get:
![63.546=[(62.9396\times x)+(64.9278\times (1-x))]\\\\x=0.6950](https://tex.z-dn.net/?f=63.546%3D%5B%2862.9396%5Ctimes%20x%29%2B%2864.9278%5Ctimes%20%281-x%29%29%5D%5C%5C%5C%5Cx%3D0.6950)
Percentage abundance of
isotope = 
Percentage abundance of
isotope = 
Hence, the percentage abundance of
and
isotopes are 69.50% and 30.50% respectively.