The general properties of Group 1 alkali metals are:
1. They form cations.
2. They are highly reactive.
3. They have a charge of +1.
4. They form ionic compounds.
5. When their oxides or hydroxides are reacted in water, they form alkalis i.e. bases.
6. They are usually soft in nature.
7. They have low densities.
Answer:
mixture because mixture cane be physically sperated
The specific heat of unknown material : 3.675 J/g °C
<h3>Further explanation</h3>
Given
mass of block = 22.5 g
Q = heat = 2067 J
Δt=25 °C
Required
The specific heat
Solution
Heat can be formulated :
Q = m.c.Δt
Input the value :
2067 J = 22.5 g x c x 25 °C
c = 3.675 J/g °C
Answer:
Temperature = 6.91K
Explanation:
Temperature = T
Number of Moles = 2.49moles
Volume = 1.0L
Pressure = 143kPa
R = 8.31kPa*L/mol.K
From ideal gas equation,
PV = nRT
P = pressure of the ideal gas
V = volume which the gas occupies
n = number of moles of the gas
R = ideal gas constant
T = temperature of the ideal gas
PV = nRT
T = PV / nR
T = (143 * 1) / (2.49 * 8.31)
T = 143 / 20.6919
T = 6.91K
The temperature of the gas is 6.91K
The number of liters produced when 126g of glucose is completely reacted with O2 is calculated as follows
find the moles of C6H12O6 used that is moles = mass /molar mass
= 126g /180 g/mol = 0.7 moles
from the equation
C6H12O6 +6O2 = 6CO2 +6 H2O
the reacting ratio of C6H12O6 to Co2 is 1:6 therefore the moles of CO2 = 0.7 x6/1= 4.2 moles
At STP 1 moles of a gas = 22.4 L
what about 4.2 L = how many liters
cross multipication
= (4.2moles x 22 .4 L)/ 1mole = 94.1 L