Answer:
10.7 g of KOH
Explanation:
First of all, we determine the reaction:
2K (s) + 2H₂O(l) → H₂(g) + 2KOH(aq)
We convert the mass of K, to moles → 7.5 g . mol/39.1 g = 0.192 moles
Ratio is 2:2, so the moles I have of K must produce the same moles of KOH. In this case, the produces moles of KOH are 0.192 moles.
We convert the moles to mass, to finish the answer:
0.192 mol . 56.1g /1mol = 10.7 g of KOH
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Chlorite is ClO2^-1, and potassium is K with a charge of +1. So, we would write is as KClO2, since the charges cancel out with each other.
35.9g x 1 mol/ 2.016g x 22.4 L/ 1 mol= 398.89 L
