The purpose of an engineering notebook is to support documented work that could potentially be patentable. hope you found this helpful!
Answer:
C
Explanation:
I just did the test on enginuity and it also is the only one that makes sence
To solve this problem we will apply the concepts related to real power in 3 phases, which is defined as the product between the phase voltage, the phase current and the power factor (Specifically given by the cosine of the phase angle). First we will find the phase voltage from the given voltage and proceed to find the current by clearing it from the previously mentioned formula. Our values are


Real power in 3 phase

Now the Phase Voltage is,



The current phase would be,

Rearranging,

Replacing,


Therefore the current per phase is 2.26kA
I think it’s b sry if I’m wrong tho