PH= log[H3O+]
10.25=log [H3O+]
[H3O+] = 10^10.25
[H3O+]= 1.778 ×10^10
Answer:
0.21 g
Explanation:
The equation of the reaction is;
NaCl(aq) + AgNO3(aq) -----> NaNO3(aq) + AgCl(s)
Number of moles of NaCl= 0.0860 g /58.5 g/mol = 0.00147 moles
Number of moles of AgNO3 = 30/1000 L × 0.050 M = 0.0015 moles
Since the reaction is 1:1, NaCl is the limiting reactant.
1 mole of NaCl yields 1 mole of AgCl
0.00147 moles of NaCl yields 0.00147 moles of AgCl
Mass of precipitate formed = 0.00147 moles of AgCl × 143.32 g/mol
= 0.21 g
Answer:
1.44 L
Explanation:
Since 25 is constant it is no use. Now, rearrange the gas formula. You should get...
P1V1/T2=P2V2T1
Next, rearrange to fit the problem. You should get...
V2=P1V1/P2
Fill in our values and solve. You should get 1.44 L
We can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.
- Hope that helps! Please let me know if you need further explanation.
Answer:
The final pressure of the gas is:- 21.3 kPa
Explanation:
Using Boyle's law
Given ,
V₁ = 10.0 L
V₂ = 45.0 L
P₁ = 96.0 kPa
P₂ = ?
Using above equation as:
The final pressure of the gas is:- 21.3 kPa
3644000 rounded to 2 significant figures is equivalent to 3.6
