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Mademuasel [1]
3 years ago
6

Classify the type of reaction between aluminum solid and oxygen gas.

Chemistry
2 answers:
Yanka [14]3 years ago
7 0
It would be a synthesis reaction
zysi [14]3 years ago
3 0
It’s a synthesis reaction.
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The oxidizing agent our bodies use to obtain energy from food is oxygen (from the air). If you breathe 15 times a minute (at res
Misha Larkins [42]

Answer:

Explanation:

Given parameters:

Number of breathe per minute = 15times

Volume of air per breath = 0.5L

Percentage of oxygen in air = 21%

Solution

There are 24 hours in a day.

 60minutes makes a hour in a day,

I will breathe:

           15 times x 60 x 24  = 21600 times in a day

The volume of air I will take in per day:

       A breathe = 0.5L of air

    21600breathe = 0.5 x 21600 = 10800L of air

Volume of oxygen I will breathe per day:

    \frac{21}{100} x 10800 = 2268L of oxygen

7 0
3 years ago
Sound molecules can "stack up" in front of airplanes traveling at very high
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D. Sonic booms. Hope this helps
7 0
4 years ago
How many moles of 18L of NH3 at 30 celcius and 912 mmHg? how many grams?
babymother [125]
Answer is: mass of ammonia is 14.76 grams and amount is 0.87 moles.<span>
V(NH</span>₃<span>) = 18 L.
T = 30°C = 303.15 K.
p = 912 mmHg ÷ 760 mmHg/atm= 1.2 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
n</span> = p·V / R·T.
n(NH₃) = 1.2 atm ·18 L / 0.08206 L·atm/mol·K · 303.15 K.
n(NH₃) = 0.87 mol.
m(NH₃) = n(NH₃) · M(NH₃).
m(NH₃) = 0.87 mol · 17 g/mol.
m(NH₃) = 14.76 g.<span>

</span>
6 0
4 years ago
I think I'm allergic to garlic powder. Tonight I am making pasta and will not use garlic powder this time. If I get itchy or not
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Answer:

Explanation:

A garlic allergy is rare. If you're allergic to garlic, you can be allergic to cooked or raw garlic, or to all forms. A garlic allergy is caused when your body's immune system mistakenly identifies garlic as being harmful and produces antibodies in an attempt to fight it off. Does this help?

6 0
3 years ago
Read 2 more answers
A first-order reaction has a half-life of 29.8 s . How long does it take for the concentration of the reactant in the reaction t
lutik1710 [3]

Answer : The time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

Explanation :

Half-life = 29.8 s

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{29.8s}

k=0.0232s^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.0232s^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = x M

a - x = amount left after decay process = x-\frac{1}{4}\times (x)=\frac{3}{4}\times (X)=\frac{3x}{4}M

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0232s^{-1}}\log\frac{x}{(\frac{3x}{4})}

t=12.4s

Therefore, the time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

7 0
4 years ago
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