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erik [133]
3 years ago
13

If the child has a mass of 13.9 kg, calculate the magnitude of the force in newtons the mother exerts on the child under the fol

lowing conditions. (b) The elevator accelerates upward at 0.898 m/s2. 148.702 N
Physics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer:

hi how are you doing today Jasmine

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If a vector that is 3 cm long represents 30 km/h, what velocity does a 5 cm long vector which is drawn using the same scale repr
s2008m [1.1K]
That way the 5 cm long vector represents 50 km/h
5 0
3 years ago
Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your
blondinia [14]

Answer:

Time taken, t = 3.53 seconds

Explanation:

It is given that,

The formula for calculating the time t is given by :

t=(0.25)s^{1/2}...... (1)

Where

s is the distance in feets

We need to find the time taken by the stone to drop a distance of 200 feets, s = 200 feets

Put the value of s in equation (1) such that,

t=(0.25)\times (200)^{1/2}

t = 3.53 seconds

So, the time taken by the object is 3.53 seconds. Hence, this is the required solution.

4 0
3 years ago
A6 kg bag of rice is on the top shelf at a grocery store.
netineya [11]

Answer:

<h2>117.6 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 6 × 9.8 × 2

We have the final answer as

<h3>117.6 J</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
When making maps of the large-scale universe, astronomers estimate distances to the vast majority of galaxies by using:
Vesnalui [34]

Answer:

<em>The comoving distance and the proper distance scale</em>

<em></em>

Explanation:

The comoving distance scale removes the effects of the expansion of the universe, which leaves us with a distance that does not change in time due to the expansion of space (since space is constantly expanding). The comoving distance and proper distance are defined to be equal at the present time; therefore, the ratio of proper distance to comoving distance now is 1. The scale factor is sometimes not equal to 1. The distance between masses in the universe may change due to other, local factors like the motion of a galaxy within a cluster.  Finally, we note that the expansion of the Universe results in the proper distance changing, but the comoving distance is unchanged by an expanding universe.

4 0
3 years ago
Explain how the gas laws apply to the act of breathing. Describe the changes that occur in each step of the process in terms of
MrRa [10]
<span>When you in inhale, you move your diaphragm down increasing the volume of the cavity in your ribs (its called pleural cavity). This lowers the pressure inside your lungs. When the pressure in your lungs is less than the atmospheric pressure, air draws inwards. Ideal gas law: PV=nRT -> assume nRT are constant for our purposes. then we allow one system to be equal to the same system at different conditions, thus: P1V1=P2V2 (Boyles Law) assume P1=1 atm and V1=1 L (keeping the numbers simple to avoid confusion). when the V is increased (for example say doubled) V2=2 L, then: (1 atm)*(1 L)=P2*(2 L) -> P2=0.5 atm The pressure was decreased. Apply the same logic for exhalation.</span>
4 0
3 years ago
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