Answer:
0.856.
Explanation:
Lets represent the irreversible elementary gas phase equation of reaction as
A + B -----------------------------------> C + D
We have that the percentage of conversion is 80%.
The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.
Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.
Now, let's make use of the equation below;
J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).
0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .
k = 4.95 dm^6/ kg.cat .mol.min
The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.
Thus, making use of the equation (1) again, we have that;
{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.
Therefore, a/1 - a = 5.964.
5.964( 1 - a) = a.
5.964 - 5.964a = a.
5.964 = a + 5.964a.
5.964 = 6.964a.
a = 5.964/ 6.964 = 0.856.
