A 50 kg boy runs and jumps with a forward velocity of 1.5 m/s into a 125 kg stationary boat.
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As per the question a frog jumps 5 m towards east.
Frog again jumps 2 m north.
Let the displacement along east is denoted by vector A and the displacement towards north is denoted as vector B.
Hence magnitude of A = 5 m
Magnitude of B = 2 m
We are asked to calculate the total displacement.
Here the angle between them is 90 degree as A is towards east and B is towards north.
As per parallelogram law of vector addition,the magnitude of total displacement [R] will be-
[cos90= 0]
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