Explanation:
1) Work done = force x distance x cos(θ)
= 0.15 x 6 x cos(30)
= 0.779
2) Ek = ½mv²
v = acceleration due to gravity so 9.81
Ek = ½(2)(9.81)²
Ek = 96.2361
3) v = (√(2em)) / m
= (√(2(96.2361)(2)) / 2
= 9.81 so especially with no time given, I can only assume the acceleration due to gravity but take it with a pinch of salt.
Answer:
Final Volume of the gas = 0.1 m^3
Explanation:
Check the attached file for the calculations involved in this solution
Answer:
Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.
Answer:
When the circuit switch is off, no electricity will flow and then the circuit is called an open circuit. Electricity will not flow in open circuit.
Answer:
critical clearing angle = 70.3°
Explanation:
Generator operating at = 50 Hz
power delivered = 1 pu
power transferable when there is a fault = 0.5 pu
power transferable before there is a fault = 2.0 pu
power transferable after fault clearance = 1.5 pu
using equal area criterion to determine the critical clearing angle
Attached is the power angle curve diagram and the remaining part of the solution.
The power angle curve is given as
= Pmax sinβ
therefore : 2sinβo = Pm
2sinβo = 1
sinβo = 0.5 pu
βo =
⁰
also ; 1.5sinβ1 = 1
sinβ1 = 1/1.5
β1 =
= 41.81⁰
∴ βmax = 180 - 41.81 = 138.19⁰
attached is the remaining solution
The critical clearing angle =
≈ 70.3⁰