Ask question

Ask question

All categories

3 years ago

13

In particular, a system may or may not be (1) Memoryless, (2) Time invariant, (3)Linear, (4) Casual, (5) Stable.

1 answer:

egoroff_w [7]3 years ago

4 0

Answer:

a. True

Explanation:

A system may be sometimes casual, time invariant, memoryless, stable and linear in particular.

Thus the answer is true.

A system is casual when the output of the system at any time depends on the input only at the present time and in the past.

A system is said to be memoryless when the output for each of the independent variable at some given time is fully dependent on the input only at that particular time.

A system is linear when it satisfies the additivity and the homogeneity properties.

A system is called time invariant when the time shift in the output signal will result in the identical time shift of the output signal.

Thus a system can be time invariant, memoryless, linear, casual and stable.

You might be interested in

f the rope is drawn toward the motor M at a speed of vM= (5t3/2) m/s, where t is in seconds, determine the speed of the cylinder

SCORPION-xisa [38]

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED Rharden you could either me or leave

harden you could either me or leave

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED RVV

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED R

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED R

harden you could either me or leave

GO WATCH AFTER OUT NOW RADDED R

4 0

3 years ago

2.5 Critically discuss how community needs may influence your choice of a career

GaryK [48]

Different communities will have a demand for different careers. Areas with a large number of school will have a higher demand for teachers. The community needs professors, pays them well, you might decide to choose that path

3 0

3 years ago

A rectangular plate casting has dimensions 200mm x 100mm x 20mm. The riser for this sand casting mold is in the shape of a spher

9966 [12]

Answer:

Diameter of riser =6.02 mm

Explanation:

Given that

Dimensions of rectangular plate is 200mm x 100mm x 20mm.

Volume of rectangle V= 200 x 100 x 20 $mm^3$

Surface area of rectangle A

A=2(200 x 100+100 x 20 +20 x 200) $mm^2$

So V/A=7.69

We know that

Solidification times given as

$t=K\left(\dfrac{V}{A}\right)^2$ -----1

Lets take diameter of riser is d

Given that riser is in spherical shape so V/A=d/6

And

Time for solidification of rectangle is 3.5 min then time for solidificartion of riser is 4.2 min.

Lets take $\dfrac{V}{A}=M$

$\dfrac{M_{rac}}{M_{riser}}=\dfrac{7.69}{\dfrac{d}{6}}$

Now from equation 1

$\dfrac{3.5}{4.2}=\left(\dfrac{7.69}{\dfrac{d}{6}}\right)^2$

So by solving this d=6.02 mm

So the diameter of riser is 6.02 mm.

3 0

3 years ago

Which welding processes normally use a constant current power source? (Select all that apply) PLEASE HELP

Furkat [3]

Answer:

Explanation:

GTAW AND GMAW

5 0

3 years ago

An automobile tire with a volume of 0.8 m3 is inflated to a gage pressure of 200 kPa. Calculate the mass of air in the tire if t

saveliy_v [14]

Answer:

2.83 kg

Explanation:

Given:

Volume, V = 0.8 m³

gage pressure, P = 200 kPa

Absolute pressure = gage pressure + Atmospheric pressure

= 200 + 101 = 301 kPa = 301 × 10³ N/m²

Temperature, T = 23° C = 23 + 273 = 296 K

Now,

From the ideal gas equation

PV = mRT

Where,

m is the mass

R is the ideal gas constant = 287 J/Kg K. (for air)

thus,

301 × 10³ × 0.8 = m × 287 × 296

or

m = 2.83 kg

3 0

4 years ago