You knew that this question is ridiculously easy. So, just to
make it harder, you decided not to let us see the picture, so
that we could not "examine the circuit".
The description is talking about a parallel circuit. The other
kind is a series circuit, and that one has no forks in the road.
A circle has a revolution of 360°. Since there are 12 hour markings, each hour interval has an angle of 30°. In radians, that would be equal to π/6 radians. So, in every 1 hour that passes, it covers π/6 of an angle. So, the angular velocity denoted as ω is π/6 ÷ 1 hour = π/6 rad/h. We can compute the average linear velocity, v, from the relationship:
v = rω, where r is the radius of the circle which is the length of the hour hand
v = (2.4 cm)(π/6 rad/h)
v = 1.257 cm/hour
Therefore, the average velocity is 1.257 cm per hour.
For the average acceleration, it is equal to zero. The hands of the clock move at a constant velocity. Since acceleration is the change of velocity per unit time, there is no change of velocity because it's constant. That's why it is zero.
The car's velocity is (distance + direction) / (time) =
(75 km-north) / (1.5 hrs) =
(75/1.5) (km-north/hr) = 50 km/hr north.
Answer:
the pressure will decrease by 1/2
Explanation:
PV=nRT
P=(nRT)/(V)
nRT are all constant so they will equal 1
V is 2
P=1/2
