An eclipse is a phenomenon of an astronomical object being obscured by something. In this case, it is the Moon that is being obscured from sunlight by Earth's shadow. Answer is D.
Answer:
But once the core runs out of hydrogen, the star starts to contract again briefly, until a shell of hydrogen around the core becomes hot enough to fuse into helium. When this happens, the radiation pushes the outer layers of the star far out into space, turning the star into a red giant
Explanation:
Correct?
<h2>Answer</h2>
1 V = 1 kg m2 s−² C
1 V = 1 kg m2 s−³ A−1
(one kilogram meter squared per second cubed per ampere)
<h2>Explanation</h2>
<em>The work required to move an electric charge of one coulomb through an electrical potential difference of one volt,</em>
<h2> Volts = Joules / Coulombs</h2><h2 />
Joules = Newton x metre
Volts = Nm / coulombs
Newton = kg x metre / second ²
Volts = kg x metre / second ² coulombs
Volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (c)
<h3>For further:</h3>
Coulomb = Amp * second
Volts = kg x metre / second ³ Amp
<h2 />
Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².
Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.
Given,
Radius of flywheel (r) = 1.96 cm = 0.0196m
Angular acceleration (α)= 13.0 rad/s²
The tangential acceleration formula is at=rα
where, α is the angular acceleration, and r is the radius of the circle.
using the formula; at=rα = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².
The tangential acceleration is 0.2548 m/s².
Learn more about the Tangential acceleration with the help of the following link:
brainly.com/question/15743294
#SPJ4
Initial momentum = 2 * m v
so if 1 ball popped out with 2 v momentum would be conserved
but the initial kinetic energy of the two balls is
1/2 m v^2 + 1/2 m v^2 = m v^2
But the kinetic energy of one ball with twice the speed would be
KE = 1/2 m (2 v)^2 = 2 m v^2 thus violating conservation of energy