Answer:
it should be:swept clean,contain rags,not be used for cargo
Answer:the maximum normal stress=62.1 Ksi
maximum Shear stress, τmax=31.05ksi
Explanation:
Given pressure of inner vessel=60psi
t=thickness of the wall of the vessel=0.375 in
r = inner radius= d₀/2 -t
d₀=13-ft to inches = 13 x12 =156 in/2
=78 - 0.375
=77.625 in
The maximum normal stress in a spherical container is calculated as
σ=pr/2t
= 60 x 77.625/ 2 x0.375
6210psi / 100 = 62.1 Ksi
maximum Shear stress, τmax = σmax /2
62.1 Ksi/2
=31.05ksi
Answer:
velocity is 15.083 m/s
Explanation:
given data
length L = 1 m
Laminar to turbulent flow
xc = 0.5 m
Reynolds number Rex, c = 5 ×
solution
we take here for 350 K
= 1.81 ×
and here Reynolds number Rex, is express as
Rex = ................1
put here value at x = 0.5
5 × =
solve it we get
v = 15.083 m/s
so velocity is 15.083 m/s
Answer:
Tension in wire will be
Explanation:
We have given seed of the transverse wave v = 400 m/sec
Linear density = 0.10 g/cm
We know that 1 gram = 0.001 kg
And 1 cm = 0.01 m
So
We know that speed of wave is given by , here T is tension in the wire
So
Squaring both side
T =
So tension in wire will be
Answer:
Explanation:
From the question we are told that:
Liquid density
Diameter of pipe
Diameter of venture
Specific weight of mercury P_mg
Flow rate
Area A:
Generally the Bernoulli's equation is mathematically given by
Where
Therefore
Generally the equation for pressure difference b/w manometer fluid is given as
Therefore
Therefore elevation change is mathematically given by