Every 10.0 seconds, a crest of the wave passes the pier. This means that the period of the wave is exactly 10.0 s:
which means that the frequency of the wave is
The wavelength of a wave is related to its frequency by the relationship
where v is the speed of the wave.
In this problem, v=5.6 m/s; if we use the previous formula, we find the wavelength of the wave:
Answer:
t₂ = t₁ / 5
Explanation:
Rotational kinematics using: ωf = ωi + αt
Starting from rest and speeding up:
ω₁ = 0 + αt₁ .. Eq1
Starting from ω₁ and slowing to a stop:
0 = ω₁ - 5αt₂
Substituting for ω₁ from Eq 1
0 = αt₁ - 5αt₂
5αt₂ = αt₁
5t₂ = t₁
t₂ = t₁ / 5
Answer:
it b
Explanation:
bc A water droplet falling in the atmosphere is spherical
Answer:
= -12 N
, = -80 N and = - 44 N
Explanation:
The force is related to the potential energy by the formula
F = -Δ U = - ( i ^ + j ^ + k ^)
It indicates the potential energy
U = 2xyz + 3z² + 4yx + 16
To solve this problem let's make the derivatives, to find each component of the force
= 2yz + 0 + 4y + 0 = 2yz + 4y
= 2xz + 0 + 4x + 0 = 2xz + 4x
= 2xy + 3 2z + 0 +0 = 2xy + 6z
We look for the expression for the force in each axis
= - 2yz - 4y
= -2xz -4x
= -2xy -6z
We calculate at the point P = (20 i ^ + 1j ^ + 4 k ^) m
= - 2 1 4 - 4 1
= -12 N
= - 2 20 4 - 4 20
= -80 N
= - 20 1 - 6 4
= - 44 N
We put together the expression for strength
F = (-12 i ^ - 80j ^ -44k ^) N
Answer:
Coulomb's law is:
First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:
N = (1/{e0})*C^2/m^2
then we have:
{e0} = C^2/(m^2*N)
And we know that N = kg*m/s^2
then the dimensions of e0 are:
{e0} = C^2*s^2/(m^3)
(current square per time square over cubed distance)
And knowing that a Faraday is:
F = C^2*S^2/m^2
The units of e0 are:
{e0} = F/m.