Answer: the two states that are fluid are;-
<u>#{1} liquid</u>
<u>#{2} gas </u>
Explanation:
as we know that there are mainly three states of substance
but among them only two of them can fluid and takes the shape of the container that are liquid and gas
Answer:
a) T = 608.22 N
b) T = 608.22 N
c) T = 682.62 N
d) T = 533.82 N
Explanation:
Given that the mass of gymnast is m = 62.0 kg
Acceleration due to gravity is g = 9.81 m/s²
Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.
So;
To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;
T = mg
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs the rope at a constant rate tension in the string is
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs up the rope with an upward acceleration of magnitude
a = 1.2 m/s²
the tension in the string is T - mg = ma (Since acceleration a is upwards)
T = ma + mg
= m (a + g )
= (62.0 kg)(9.81 m/s² + 1.2 m/s²)
= (62.0 kg) (11.01 m/s²)
= 682.62 N
When the gymnast climbs up the rope with an downward acceleration of magnitude
a = 1.2 m/s² the tension in the string is mg - T = ma (Since acceleration a is downwards)
T = mg - ma
= m (g - a )
= (62.0 kg)(9.81 m/s² - 1.2 m/s²)
= (62.0 kg)(8.61 m/s²)
= 533.82 N
Average speed = (total distance covered) / (time to cover the distance)
Total distance = (77km + 66km) = 143 kilometers
Time to cover the distance = 2 hours
Average speed = (143 km) / (2 hours) = 71.5 km per hour
Answer:
P=(2 nm, 8mn)
Explanation:
Given :
Position of positively charged particle at origin, 
Position of desired magnetic field, 
Magnitude of desired magnetic field, 
Let q be the positive charge magnitude placed at origin.
<u>We know the distance between the two Cartesian points is given as:</u>
<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>
as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the given point.
assuming that the second charge is placed at (x,y) nano-meters.
Therefore,
and
