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viktelen [127]
3 years ago
10

PLZ HELPPPP TIMED TESTT!!!!!!?????

Chemistry
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

my probably best answer is B

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A small diamond, which is made of pure carbon, contains too many carbon atoms to count individually. Which is closest to the num
8090 [49]

The correct answer is option C, 5.02 x 10²² carbon atoms

Atomic mass of C = 12 g/mol

According to Avogadro, 1 mole of C has 6.023 x 10²³C atoms

Now 1 mole of C is equal to 12 g

Therefore, 12 g of C = 6.023 x 10²³ C atoms

1 g of C = \frac{6.023 x 10^2^3}{12} C atoms = 5.02 x 10²² C atoms

7 0
3 years ago
Help! I am in a hurry! Will get brainliest if correct!
stira [4]

Answer:

Should be 3

Iron, cobalt, and nickel

7 0
2 years ago
Under the same conditions of solar radiation, compared with oceans the land will warm_________
aksik [14]
Land will warm faster/quicker
7 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) -->
irakobra [83]

The products will be ZnCl_2(s) + H_2(g)

<h3>Chemical reactions</h3>

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

More on chemical reactivity can be found here: brainly.com/question/9621716

#SPJ1

3 0
2 years ago
For the chemical reaction , I identify the reactant and the products .
svetlana [45]

The reactant is Mercury (II) Oxide while the products are Mercury and Oxygen separately.

This is because the reactants are typically always on the left side of the yields symbol. In this decomposition reaction, it would still be the same as at the end of the reaction, there were to products produced: Mercury and Oxygen.

Products tend to always be on the right side of the yields symbol, they're what comes out of a reaction no matter what type.

Hope this helps!

7 0
3 years ago
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