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gladu [14]
2 years ago
11

How many molecules of glucose are in 1.15 mol of glucose, C6H1206?

Chemistry
1 answer:
Akimi4 [234]2 years ago
8 0

Answer: There are 6.926\times 10^{23} molecules of glucose.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the molecules, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadro's number}}

1.15=\frac{x}{6.023\times 10^{23}}

x=1.15\times 6.023\times 10^{23}=6.926\times 10^{23}

Thus there are 6.926\times 10^{23} molecules of glucose.

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a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the
svet-max [94.6K]

Answer: The mass density is 1166.36 kg/m^{3}.

Explanation:

Given: Weight of sample in air (F_{air}) = 500 N

Weight of sample in alcohol (F_{alc}) = 200 N

Specific gravity = 0.7 = 0.7 \times 1000 = 700 kg/m^{3}

Formula used to calculate Buoyant force is as follows.

F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N

Hence, volume of the material is calculated as follows.

V = \frac{F_{B}}{\rho \times g}

where,

F_{B} = Buoyant force

\rho = specific gravity

g = acceleration due to gravity = 9.81

Substitute the values into above formula.

V = \frac{F_{B}}{\rho \times g}\\= \frac{300}{700 \times 9.81}\\= \frac{300}{6867}\\= 0.0437 m^{3}

Now, mass of the material is calculated as follows.

mass = \frac{F_{air}}{g}\\= \frac{500 N}{9.81}\\= 50.97 kg

Therefore, density of the material or mass density is as follows.

Density = \frac{mass}{volume}\\= \frac{50.97 kg}{0.0437 m^{3}}\\= 1166.36 kg/m^{3}

Thus, we can conclude that the mass density is 1166.36 kg/m^{3}.

7 0
2 years ago
A balloon is filled to a volume of 2.20L at a temperature of 22*C. The balloon is then heated to a temperature of 71*C. Find the
goldfiish [28.3K]

2.565L

Explanation:

  • Charles law states that the volume of an ideal gas at constant pressure is directly proportional to the absolute temperature.V/T=K

         V1/T1=V2/T2        

          Unit of Kelvin = 273.15

  • To get the absolute temperature, we need to convert the degree celsius temperature to kelvin.

          T1= 22+273.15= 295.15 K

          T2 = 71+273.15= 344.15 K

          V1 = 2.20 L

          V2 =?

          2.20/295.15=V2/344.15

          0.00745 x 344.15 = 2.565 L

Hence,  2.565 L is the new volume of the balloon.

3 0
3 years ago
76/304=81/k what is K and show work plez
siniylev [52]
You can cross multiply and then get k alone so it would look like this:
76         81    
-----  =   ------    =  76k= 24624
304        k            -----  -----------  =      k  =  324
                             76        76


so k is equal to 324

hope this helps have a nice day
4 0
3 years ago
1. Why don't scientists stop with the first step in the Scientific Method, making observations? A. They don't trust their own ob
natulia [17]

Answer:

Explanation:

Scientists don't stop with the first step of their experiment because they want other scientists' opinions because they may not trust their own observations.

                     OR

Scientists don't stop with the first step of their experiment because they would rather plan and run experiments than just observe the world around them    

       

Hope any one of these helps you

5 0
3 years ago
The decomposition of 57.0 g of Fe2O3 results in Consider the following reaction. 2Fe2O3 ---> 4Fe + 3O2 deltaH degree rxn = +
lozanna [386]

Answer:

The correct answer is option E.

Explanation:

2Fe_2O_3\rightarrow 4Fe + 3O_2 \Delta H^o_{rxn} = 824.2 kJ

Mass of ferric oxide decomposed = 57.0 g

Moles of ferric oxide decomposed = \frac{57.0 g}{160 g/mol}=0.35625 mol

According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.

Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:

\frac{824.2 kJ}{2}\times 0.35625 =146.81 kJ\approx 147 kJ

So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.

3 0
3 years ago
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