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3 years ago

Part of a chemical equation is shown below 2koh + h2so4 .

Chemistry

2 answers:

GREYUIT [131]3 years ago

4 0

Answer: K2SO4 + 2H2O

Explanation:

I got it right

iren2701 [21]3 years ago

4 0

Answer:

K2SO4 + 2H2O

Explanation:

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Simply parmanent tissue real life application please help it's for my project

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The simple tissues are parenchyma, sclerenchyma and collenchyma. Chlorenchyma is a parenchyma, having chloroplast. It is a simple permanent tissue, having chloroplast.

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3 years ago

All the members of this family (inner transition metals) are both ______________ and _____________.

avanturin [10]

Answer:

The actinides and the lanthanides

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3 years ago

Read 2 more answers

3. Give one example of an element and one

zhenek [66]

Answer:

Element: H (hydrogen)

Compound: H2O (water)

Explanation: An element is made up of a singular atom while a compound is made up of 2 or more

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3 years ago

The equilibrium constant (Kp) for the decomposition of phosphorus pentachloride (PCl5) to phosphorus trichloride (PCl3) and mole

Oksanka [162]

Answer: The partial pressure of $Cl_2$ is 1.86 atm

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

The given balanced equilibrium reaction is,

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

Pressure at eqm. 0.973 atm 0.548atm x atm

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{(p_{PCl_3}\times (p_{Cl_2})}{(p_{PCl_5})}$

Now put all the given values in this expression, we get :

$1.05=\frac{(0.548)\times (x)}{(0.973)}$

By solving the term 'x', we get :

x = 1.86 atm

Thus, the partial pressure of $Cl_2$ is 1.86 atm

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4 years ago

Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of

natima [27]

Answer:

21 KJ/mol

Explanation:

For this question, we have to start with the linear structure of 2-methylbutane. With the linear structure, we can start to propose all the Newman projections keep it in mind that the point of view is between carbons 2 and 3 (see figure 1).

Additionally, we have several energy values for each interaction present in the Newman structures:

-) Methyl-methyl gauche: 3.8 KJ/mol

-) Methyl-H eclipse: 6.0 KJ/mol

-) Methyl-methyl eclipse: 11.0 KJ/mol

-) H-H eclipse: 4.0 KJ/mol

Now, we can calculate the energy for each molecule.

Molecule A

In this molecule, we have 2 Methyl-methyl gauche interactions only, so:

(3.8x2) = 7.6 KJ/mol

Molecule B

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

Molecule C

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule D

In this molecule, we have three Methyl-H eclipse interaction, so:

(6*3) = 18 KJ/mol

Molecule E

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule F

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

3 0

3 years ago