Answer:
As collision is elastic,thus we can use conservation of momentum equation
mA=0.2 kg
(vB)1=0 m/s.......................as it is on rest before collision
(vA)1=4 m/s
(vA)2=-1 m/s
(vB)2=2 m/s
using equation
(mA*vA+mB*vB)1= (mA*vA+mB*vB)2
Where 1 and 2 represents before and after collision
(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)
0.8=-0.2+(2mB)
mass of object B=mB=0.3 Kg
Following the initial 4.0 seconds of travel, the cart moved 32m.
<h3>What is an equation of motion?</h3>
Physicists use equations of motion to describe how a physical system behaves in terms of how its motion changes over time.
The behavior of a physical system is described by the equations of motion in more detail as a collection of mathematical functions expressed in terms of dynamic variables. These variables typically comprise time and spatial coordinates, but they could also have momentum components. The most flexible option is generalized coordinates, which can be any useful variable that is a component of the physical system. In classical mechanics, the functions are defined in a Euclidean space, while curved spaces are used in relativity instead. The equations are the answers to the differential equations describing the motion of the dynamics of the dynamics of a system are known. The amount of motion changes according to the strength of the force and does so in the direction of the force's applied straight line.
To know more about equations of motion, click here:
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Answer:
8.6 m
Explanation:
The motion of a soccer ball is a motion of a projectile, with a uniform motion along the horizontal (x-) direction and an accelerated motion along the vertical (y-) direction, with constant acceleration
towards the ground (we take upward as positive direction, so acceleration is negative).
The initial velocity along the vertical direction is

Now we can consider the motion along the vertical direction only. the vertical velocity at time t is given by:

At the point of maximum height,
, so we can find the time t at which the ball reaches the maximum height:

And now we can use the equation of motion along the y-axis to find the vertical position of the ball at t=1.33 s, which corresponds to the maximum height of the ball:
